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serg [7]
3 years ago
8

Mathphys Help help help

Physics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

1030 mph

Explanation:

The new velocity equals the initial velocity plus the wind velocity.

First, in the x (east) direction:

vₓ = 335 mph + 711 cos 19° mph

vₓ = 1007 mph

And in the y (north) direction:

vᵧ = 0 mph + 711 sin 19° mph

vᵧ = 231 mph

The net speed can be found with Pythagorean theorem:

v² = vₓ² + vᵧ²

v² = (1007 mph)² + (231 mph)²

v ≈ 1030 mph

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We know the maser radiowave has a frequency f of 1,420,405,751.786 cycles/s

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If 1h=3600s and we already know the amount of cycles per second 1,420,405,751.786 cycles/s, then:

1,420,405,751.786 \frac{cycles}{s}(3600s)=5.11(10)^{12} cycles This is the number of cycles in an hour

<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be 4.6(10)^{9} years?</h2>

Firstly, we have to convert this from years to seconds:

4.6(10)^{9} years \frac{365 days}{1 year} \frac{24 h}{1 day} \frac{3600 s}{1 h}=1.45(10)^{17} s

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1,420,405,751.786 cycles/s (1.45(10)^{17} s)=2.06(10)^{26} cycles This is the number of cycles in the age of the Earth

<h2>d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>

If we have 1 second out for every 100,000 years, then:

4.6(10)^{9} years \frac{1 s}{100,000 years}=46000 s

This means the maser would be 46000 s off after a time interval equal to the age of the earth

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