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serg [7]
3 years ago
8

Mathphys Help help help

Physics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

1030 mph

Explanation:

The new velocity equals the initial velocity plus the wind velocity.

First, in the x (east) direction:

vₓ = 335 mph + 711 cos 19° mph

vₓ = 1007 mph

And in the y (north) direction:

vᵧ = 0 mph + 711 sin 19° mph

vᵧ = 231 mph

The net speed can be found with Pythagorean theorem:

v² = vₓ² + vᵧ²

v² = (1007 mph)² + (231 mph)²

v ≈ 1030 mph

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Answer:

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Explanation:

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Range R = 77 m

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  v_{o} = \sqrt{\frac{gR}{\sin 2 \alpha } }

  v_{o} = \sqrt{\frac{9.8 \times 77}{\sin 26} }                              ( ∵ g = 9.8 \frac{m}{s^{2} } )

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Which property of light is a constant in a vacuum?
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3 years ago
Read 2 more answers
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Answer:

Explanation:

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= 6300 + 300 = 6600 km

= 6600 x 10³

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v₀ = √gR , ( if height  is small with respect to radius )

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