Answer:
The maximum mass of water that could be produced by the chemical reaction is 10.1 g
Explanation:
The equation of reaction involves the combustion of 2 moles of hexane (C6H14) with 19 moles of oxygen (O2) to produce 12 moles of carbon dioxide (CO2) and 14 moles of water (H2O)
From the equation of reaction above,
2 moles of C6H14 (172 g) produced 14 moles of H2O (252 g)
6.9 g of C6H14 would produce (6.9×252/172) = 10.1 g of water (to 3 significant figures)
Also, from the equation of reaction,
19 moles of O2 (608 g) produced 14 moles of H2O (252 g)
17.3 g of O2 would produce (17.3×252/608) = 7.17 g of water (to 3 significant figures)
Maximum mass of water produced = 10.1 g
