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stepladder [879]
3 years ago
7

Problem PageQuestion Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose

6.9 g of hexane is mixed with 17.3 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits.
Physics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

The maximum mass of water that could be produced by the chemical reaction is 10.1 g

Explanation:

The equation of reaction involves the combustion of 2 moles of hexane (C6H14) with 19 moles of oxygen (O2) to produce 12 moles of carbon dioxide (CO2) and 14 moles of water (H2O)

From the equation of reaction above,

2 moles of C6H14 (172 g) produced 14 moles of H2O (252 g)

6.9 g of C6H14 would produce (6.9×252/172) = 10.1 g of water (to 3 significant figures)

Also, from the equation of reaction,

19 moles of O2 (608 g) produced 14 moles of H2O (252 g)

17.3 g of O2 would produce (17.3×252/608) = 7.17 g of water (to 3 significant figures)

Maximum mass of water produced = 10.1 g

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The final momentum of the body is equal to 120 Kg.m/s.

<h3>What is momentum?</h3>

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: {\displaystyle \mathbf {p} =m\mathbf {v} . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

Given the initial momentum of the body = Pi = 20 Kg.m/s

The force acting on the body, Pf = 25 N

The time, Δt = 4-0 = 4s

The Force is equal to the change in momentum: F ×Δt = ΔP

25 × 4 = P - 20

100 = P - 20

P = 100 + 20 = 120  Kg.m/s

Therefore, the final momentum of a body is 120 Kg.m/s.

Learn more about momentum, here:

brainly.com/question/4956182

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1 year ago
An object is placed at O ona number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to
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Answer:

You have a displacement of 5 units to the right.

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First you go three to the right which lands on the 3 mark. Then you move it 4 to the left which substracts 4, landing the object at -1. Finally you move 6 to the right, and you finish at marker 5. Since displacement is not total distance but just final distance from the start point directly to end point, it is only a displacement of 5.

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Answer:

m = 105.37 kg

Explanation:

We are given;

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Now, The position of the center of mass will not change during the motion of the man.

Thus,

X_g,i = X_g,f

So,

[113(6.3) + ma]/(113 + m) = [113(3.26) + m(a +3.26)]/(113 + m)

113 + m will cancel on both sides to give;

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ma will cancel out to give;

711.9 - 368.38 = 3.26m

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