Question

Problem PageQuestion Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 6.9 g of hexane is mixed with 17.3 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits.

Answer 1

Answer:

The maximum mass of water that could be produced by the chemical reaction is 10.1 g

Explanation:

The equation of reaction involves the combustion of 2 moles of hexane (C6H14) with 19 moles of oxygen (O2) to produce 12 moles of carbon dioxide (CO2) and 14 moles of water (H2O)

From the equation of reaction above,

2 moles of C6H14 (172 g) produced 14 moles of H2O (252 g)

6.9 g of C6H14 would produce (6.9×252/172) = 10.1 g of water (to 3 significant figures)

Also, from the equation of reaction,

19 moles of O2 (608 g) produced 14 moles of H2O (252 g)

17.3 g of O2 would produce (17.3×252/608) = 7.17 g of water (to 3 significant figures)

Maximum mass of water produced = 10.1 g