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Oduvanchick [21]
3 years ago
6

1.Which two electron configurations represent elements that would have similar chemical properties? I.1s22s22p4II.1s22s22p5III.[

Ar]4s23d104p3IV. [Ar]4s23d104p4A) Iand IIB) I and IIIC) Iand IVD) IIand IVE) IIand II

Chemistry
1 answer:
Art [367]3 years ago
6 0

Answer:

Option C=  1 and 1V

Explanation:

The first one is the electronic configuration of oxygen.

O₈ =1s² 2s² 2p⁴

The IV is the electronic configuration of Selenium.

Se₄ =[Ar] 4s² 3d¹⁰ 4p⁴

Oxygen and selenium both are present in group 16. The elements present in same group showed similar chemical properties.

While the II is the electronic configuration of fluorine:

F₉ =1s² 2s² 2p⁵

and the III is the electronic configuration of arsenic.

Ar₃₃ = [Ar] 4s² 3d¹⁰ 4p³

Arsenic is present in group fifteen and fluorine is present in group 17. That's why their properties are not similar with each other and also with oxygen and selenium.

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Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

7 0
3 years ago
A train travels at a speed of 30 miles per hour. If 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per m
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The answer 
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v = </span><span>30 miles per hour
</span><span>1 mile = 1.6 kilometers

just do the calculus by changing miles to kilometers
 </span>1 mile = 1.6 kilometers, so 30 miles= 1.6 km x 30 = 48 km
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v=30 miles / hour = 48km / h = 48km / 60 mn  = 0.8 km/ mn
the answer is
<span>C- 0.8 km/min</span> 
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3 years ago
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