Answer:
a)1396.52 N
b)1396.52 N
c)
d)
Explanation:
The force experienced by the satelite is giveb by
m_{satellite}= 445 Kg
m_{earth}= 6×10^24 Kg
radius r= 1.77Re= 1.77×6.38×10^6 m
now putting values we get
⇒F= 1396.52 N
now,
also,
Um ônibus percorre a distância de 480 km, entre Santos e Curitiba, com velocidade escalar média de 80 km/h. De Curitiba a Floria
2 answers:
Answer:
10 h
Explanation:
velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo
de Santos e Curitiba:
distância (d) de 480 km, velocidade (s) de 80 km/h
de Curitiba e Florianópolis:
distância (d) de 300 km, velocidade (s) de 75 km/h
tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h
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Answer:
Second drop: 1.04 m
First drop: 1.66 m
Explanation:
Assuming the droplets are not affected by aerodynamic drag.
They are in free fall, affected only by gravity.
I set a frame of reference with the origin at the nozzle and the positive X axis pointing down.
We can use the equation for position under constant acceleration.
X(t) = x0 + v0 * t + 1/2 * a *t^2
x0 = 0
a = 9.81 m/s^2
v0 = 0
Then:
X(t) = 4.9 * t^2
The drop will hit the floor when X(t) = 1.9
1.9 = 4.9 * t^2
t^2 = 1.9 / 4.9
That is the moment when the 4th drop begins falling.
Assuming they fall at constant interval,
Δt = 0.62 / 3 = 0.2 s (approximately)
The second drop will be at:
X2(0.62) = 4.9 * (0.62 - 1*0.2)^2 = 0.86 m
And the third at:
X3(0.62) = 4.9 * (0.62 - 2*0.2)^2 = 0.24 m
The positions are:
1.9 - 0.86 = 1.04 m
1.9 - 0.24 = 1.66 m
above the floor