Um ônibus percorre a distância de 480 km, entre Santos e Curitiba, com velocidade escalar média de 80 km/h. De Curitiba a Floria
2 answers:
Answer:
10 h
Explanation:
velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo
de Santos e Curitiba:
distância (d) de 480 km, velocidade (s) de 80 km/h
de Curitiba e Florianópolis:
distância (d) de 300 km, velocidade (s) de 75 km/h
tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h
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Answer:
141.78 ft
Explanation:
When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.
Calculating the acceleration using one of Newton's equations of motion:
Note: The negative sign denotes deceleration.
When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2
Hence, we can find the minimum stopping distance using:
The minimum stopping distance is 141.78 ft.
Answer:
The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Explanation:
Given;
velocity of wave on the string with lower tension, v₁ = 35.2 m/s
the fundamental frequency of the string, F₁ = 258 Hz
<u>velocity of wave on the string with greater tension;</u>
where;
v₁ is the velocity of wave on the string with lower tension
T₁ is tension on the string
μ is mass per unit length
Where;
T₁ lower tension
T₂ greater tension
v₁ velocity of wave in string with lower tension
v₂ velocity of wave in string with greater tension
From the given question;
T₂ = 1.1 T₁
<u>Fundamental frequency of wave on the string with greater tension;</u>
<u /><u />
Beat frequency = F₂ - F₁
= 270.6 - 258
= 12.6 Hz
Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz