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vagabundo [1.1K]
4 years ago
14

The index of refraction for red light in water is 1.331, and that for blue light is 1.340. If a ray of white light enters the wa

ter at an angle of incidence of 83.00o , what are the underwater angles of refraction for the blue and red components of the light
Physics
1 answer:
UNO [17]4 years ago
8 0

Answer:

The underwater angles of refraction for the blue and red components of the light is 47.8° and 48.2°

Explanation:

Using the Snell's law

n1 * sin Ф1 = n2 sin Ф2

1 * sin 83 = n2 sin Ф2

Ф2 = sin^{-1} (\frac{1}{n2} * sin 83)

Red light

n2 = 1.331

Ф2 = sin^{-1} (\frac{1}{1.331} * sin 83) = 48.2°

Blue light

n2 = 1.340

Ф2 = sin^{-1} (\frac{1}{1.340} * sin 83) = 47.8°

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Answer:

Explanation:

a ) wave length of waves in water

= velocity / frequency

= 1482 / (18 x 1000)

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b ) Applying Doppler's effect relation

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5 0
3 years ago
Why do you think there are so many more autotrophs than consumers on Earth?<br> Helppp
goldfiish [28.3K]

There are many Autotrophs than consumers because : Autotrophs are the bases of any food chain/web

<h3>Function of Autotrophs </h3>

Autotrophs capture the energy required for every food chain or web from which sustains other organisms in the food chain form sunlight and chemicals. Also there is always more biomass present in the lower levels of the trophic system as biomass decreases as we move up the food chain.

Since autotrophs are producers, for a healthy food chain there would be more autotrophs than consumers.

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3 0
2 years ago
What is Snell law of refraction????​
Morgarella [4.7K]

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Explanation:

Snell's law (also known as Snell–Descartes law and the law of refraction) is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.

8 0
3 years ago
Read 2 more answers
The 6 kg block is then released and accelerates to the right, toward the 4 kg block. The surface is rough and the coefficient of
KatRina [158]

Answer:

v =3.41 m/s

Explanation:

given,

mass of block 1 = 6 Kg

mass of another block 2 = 4 Kg

coefficient of friction = 0.3

Assuming 6 Kg block is attached to the spring of spring constant 350 N/m

and distance between the two block is equal to 0.5 m

using formula

U = \dfrac{1}{2}kx^2

U = \dfrac{1}{2}\times 350 \times 0.5^2

   U = 43.75 J

using conservation of energy

 KE = U - f.d

where f is the frictional force acting

\dfrac{1}{2}mv^2 = 43.75- \mu m g d

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4 0
3 years ago
The armature windings of a dc motor have a resistance of 5.0 Ω. The motor is connected to a 120-V line, and when the motor reach
Snezhnost [94]

Answer:

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So new induced emf in our case is given by,

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Where V = E - E_{Induced }

  I = \frac{120-54}{5}

  I = 13.2 A

Therefore, the current in the motor in this case is 13.2 A

3 0
3 years ago
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