Answer: 
Explanation:
The frequency
of a wave is given by the following equation:

Where:
is the period
Hence:


Answer:
29.75 revolutions
Explanation:
The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is

This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:

So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's <em>circumferences</em> fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is
, which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.
Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is
revolutions
Complete Question
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?
Answer:
The magnetic field strength is 
Explanation:
The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

Making v the subject
Where m is the mass of electron
v is the velocity of electron
q charge on electron
is the potential difference
Substituting values
f

For the electron to move in a circular path the magnetic force[
] must be equal to the centripetal force[
] and this is mathematically represented as

making B the subject

r is the radius with a value = 5.4cm = 
Substituting values


Answer: A Radium
Explanation:
Thorium-232 is an alpha-emitting radionuclide, which decays to radium-228, which is a beta emitter with a half-life of about six years.
Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.
By Newton's second law,
- the net horizontal force acting on the beam is

where
are the magnitudes of the tensions in ropes 1 and 2, respectively;
- the net vertical force acting on the beam is

where
and
.
Eliminating
, we have





Solve for
.


