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AnnZ [28]
3 years ago
11

An electroscope is a simple device consisting of a metal ball that is attached by a conductor to two thin leaves of metal foil p

rotected from air disturbance in a jar. When the ball is touched by a charged body, the leaves that normally hang straight down, spread apart. Why?
Physics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

When the same charge spreads in the foil of the electroscope then there is a repulsion between the similarly charged foil.

Explanation:

An electroscope is a device which has metallic foil inside a sealed glass flask preventing in form external environmental disturbances. There is a ball connected to the foil via a conductor.

When the ball is touched by a charged body then the charge is conducted from the body to the ball via conductor to the foils of the electroscope. When the same charge spreads in the foil of the electroscope then there is a repulsion between the similarly charged foil.

When the charge is supplied to any metallic body then it spreads over the surface of the metal so as to minimize the force of repulsion between the similar charges.

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<u>Answer:</u>

<em>The correct equation for measuring the average microscopic weight  for 3 isotopes is multiply the rate of abundance by each weight and add them.</em>

<u>Explanation:</u>

To calculate the average microscopic mass of element using weights and relative abundance we have to follow the following steps.

  • Take the correct weight of each isotope (that will be in decimal form)
  • Multiply the weight of each isotope by its abundance
  • Add each of the results together.

<em>This gives the required  average microscopic weight of the three isotopes.</em>

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3 years ago
What’s the formula for work
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Answer:

Fd

Explanation:

Work is force times distance. If you push on an object really hard but it does not budge, you have still performed no work on it, because anything times zero is still zero.

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When you answer someones question how do you make it so your answer is verified??
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Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t
Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v^2=v_0^2+2ax\\

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

    = 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

F_f=ma=(1490kg)(5.55m/s^2)=8271.15N

Furthermore, you use the relation between the friction force and the friction coefficient:

F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56

hence, the friction coefficient is 0.56

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3 years ago
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