131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
_______?
a.0.835
b.0.268
c.0.422
d.0.440
e.0.499
1 answer:
For this problem we can use half-life formula and radioactive decay formula.
Half-life formula,
t1/2 = ln 2 / λ
where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days
Hence,
8.04 days = ln 2 / λ
λ = ln 2 / 8.04 days
Radioactive decay law,
Nt = No e∧(-λt)
where, Nt is amount of compound at t time, No is amount of compound at t = 0 time, t is time taken to decay and λ is radioactive decay constant.
Nt = ?
No = 1.53 mg
λ = ln 2 / 8.04 days = 0.693 / 8.04 days
t = 13.0 days
By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg
Hence, mass of remaining sample after 13.0 days = 0.499 mg
The answer is "e"
You might be interested in
Im sorry about my answer a while ago.
answer: it will not be half empty ever. because any gas take all the space of the tank. molecules are everywhere they take so much space.
Answer:
Neon is an inner gas because it’s outer <u>__shell__</u> is full of electrons.
Answer:
the catalyst is the two gray dots
B.sunligh
is reflected off the upper atmosphere
Waste materials, mining and transportation of radioactive fuels, radiation emissions from nuclear sites
