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Viefleur [7K]
3 years ago
11

If the amplitude of the resultant wave is twice as great as the amplitude of either component wave, and this wave exhibits reinf

orcement, the component waves must
Physics
2 answers:
makkiz [27]3 years ago
4 0
If wave exhibits reinforcement, the component waves must be in phase with each other. Components waves combine to form a resultant with the same wavelength but the amplitude which is greater than the amplitude of either of the individual component waves, and this happens in constructive interference.
In phase the features of the two waves they completely match at zero degrees.
Soloha48 [4]3 years ago
3 0

Answer choices are:

A. be traveling in the opposite direction of the resultant wave.

B. have a different frequency than the resultant wave.

C. be in phase with each other.

D. have a different wavelength than the resultant wave.

____________________________________________________________

Correct answer choice is:

C. Be in phase with each other.

____________________________________________________________

Explanation:

Components waves mix to produce a resultant with the equivalent wavelength but the amplitude which is bigger than the amplitude of both of the unique component waves, and this results in constructive interference, which states that the interference of two or more waves of identical frequency and phase, constructing in their respective reinforcement and constructing a single amplitude equivalent to the total of the amplitudes of the unique waves.

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A 34.0 %-efficient electric power plant produces 800 MW of electric power and discharges waste heat into 20∘C ocean water. Suppo
mojhsa [17]

Answer:

77647

Explanation:

\eta = Efficiency = 34%

Power used in 1 home = 0.02 MW

Total power is

P=\dfrac{800}{\eta}\\\Rightarrow P=\dfrac{800}{0.34}\\\Rightarrow P=2352.94117\ MW

Waste of power

2352.94117-800=1552.94117\ W

Number of homes would be given by

n=\dfrac{1552.94117}{0.02}=77647.0585\ homes

The number of homes that could be heated with the waste heat of this one power plant is 77647

8 0
3 years ago
A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?
Ad libitum [116K]
Diameter = 0.170 meter
Circumference = 0.170 π meters

530 rpm = 530 circumferences / minute

               =  (530 x 0.170 π meters) / minute

               =      283.06 meter.minute

               =        4.72 meters/second
8 0
3 years ago
Which is not an example of a scalar?<br><br> a. 2t/s<br> b. 3kg<br> c. 6.2m north<br> d. -100c
xxMikexx [17]
C because I’m a teacher
4 0
3 years ago
Why do things become hot or cold?<br> Relate to Thermal Energy and The Law of Conservation of Energy
Mekhanik [1.2K]

<u>Answer:</u>

Things become hot and cold because of the transfer of energy.

<u>Explanation:</u>

The energy possessed by an object or system is called thermal energy and heat is the flow of this energy. While the law of conversation of energy states that energy is not destroyed or created, it just transfers from one object to another.  

When a hot object is placed in normal conditions, it transfers heat to the environment until both are at the same temperature and heat transfers from the environment to the cold objects placed in normal conditions.

4 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
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