Answer:
need the points my bad bro
Explanation:
Answer:
11.4 m
Explanation:
We are given that
Total distance traveled by cab,d=214 m
Maximum speed of cab=v=315 m/min=
1 min =60 s
Acceleration of cab=
We have to find the distance traveled by the cab while accelerating to full speed from rest.
Initial speed o f cab=u=0
Substitute the values in the formula
Hence, the cab travel 11.4 m from rest to full speed.
-Positively charged nucleus
-Empty spaced
-Dense core
Diamond,Aluminium,<span>Gallium</span>
It’s 49% of its original gig hope this helps!