Answer:
4 seconds both, due to constant acceleration.
Explanation:
Acceleration is speed change over time as magnitude, then for a) a=(31-21)m/s / t, then we can calculate t as (31-21)m/s / a = (31-21)m/s / 2,5 m/s^2 = 4 seconds. b) a=(61-31)m/s / t, again t=(61-51)m/s / a=(61-51)m/s / 2,5 m/s^2 = 4 seconds.
Answer:
She will have to ride her scooter approximately 10 minutes.
Answer:
The frequency of oscillations is 7 Hz
Explanation:
Given;
mass of car, = 1700 kg
mass of driver, = 66 kg
compression of the spring, x = 5mm = 0.005 m
The frequency of the oscillation is given as;
where;
k is force constant
m is the total mass of the car and the driver
m = 1700 kg + 66 kg = 1766 kg
Weight of the car and the driver;
W = mg
W = 1766 x 9.8
W = 17306.8 N
Apply hook's law, to determine the force constant;
F = kx
W = F
Thus, k = W/x
k = 17306.8 / 0.005
k = 3461360 N/m
Now, calculate the frequency
Therefore, the frequency of oscillations is 7 Hz
A man pushes a couch across the room is the answer!
Answer:
hello your question is incomplete attached below is the complete question
answer: Fg / Fe does not change ; it is the same nonzero value for all separations ( A )
Explanation:
Given that distance between proton and electron is 1 cm
Fg = Gm1m2 / r^2
where :
G ( gravitational constant )= 6.67 * 10^-11 Nm^2 / kg^2
m1 ( mass of proton ) = 1.67 * 10^-27 kg
m2 ( mass of electron ) = 9.11 * 10^-31 kg
Electrical force
Fe = kq1q2 / r^2
k = 9*10^9
hence ;
Fg / Fe = (Gm1m2 / r^2) / (kq1q2 / r^2 )
= Gm1m2 / kq1q2