Answer:
The tangential speed of the tack is 8.19 m/s.
Explanation:
The wheel rotates 3.37 times a second that means wheel complete 3.37 revolutions in a second. Therefore, the angular speed ω of the wheel is given as follows:
Use the relation of angular speed with tangential speed to find the tangential speed of the tack.
The tangential speed v of the tack is given by following expression
v = ω r
Here, r is the distance to the tack from axis of rotation.
Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.
v = 21.174 × 0.387
v = 8.19m/s
Thus, The tangential speed of the tack is 8.19 m/s.
Answer:
2 N
Explanation:
From the question, it's given that
Mass m = 0.2 kg
Acceleration a = 10 m/s^2
The force a soccer goalie experience when stopping a ball will be equal to the force at which the ball is being kicked. This is
F = ma
Substitute all the parameters into the formula
F = 0.2 × 10
F = 2 Newton.
<h2>Answer: protons and neutrons.
</h2>
The atomic nuclei of almost all elements consist of protons and neutrons.
The nucleus of an atom has very small dimensions. However, it <u>occupies its central part and concentrates more than 99% of its total mass.
</u>
It is in the nucleus that the protons (positive charge) and neutrons (neutral charge) are found.
Answer:
The frequency of the photon is 
.
Explanation:
Given that,
Energy 
We need to calculate the energy
Using relation of energy
Where, 
= energy spacing
Put the value of h into the formula
Hence, The frequency of the photon is .
