Answer:
The shaft work generated per kilogram is 
Explanation:
Given:
Temperature 
K
Initial Pressure 
MPa
Final pressure 
MPa
From the table superheated,
and 
Work done by shaft is,
But here efficiency is 0.56,
So work generated per kg is,
Work = 
Work = 
Therefore, the shaft work generated per kilogram is
<h2>Answer:</h2>
<h3>Required Answer is as follows :-</h3>
- 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²
- ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²
- ¾ = m₁ × (V)²/m₂ × (V²/4)
<h3>Now,</h3>
- ∆m = m₂ - m₁
- ∆m = 16m₂/3 - m₁ = 13m₁/3
- Ratio = (13m₁/3)/ m₁
- Ratio = 13/3
Ratio = 13:3
<h3>Know More :-</h3>
Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.
A television transforms electric energy into sound energy and radiant energy.
<h3>What is energy transformation?</h3>
Energy transformations are processes that convert energy from one type into another. Any type of energy use must involve some sort of energy transformation.
Some examples of energy transformations are, A television converts electric energy into sound and light energy. Lightbulbs convert electric energy into light energy. A hair dryer converts electrical energy into thermal and sound energy.
Learn more about Energy transformations here,
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Answer:
represents the fact that there is no diagram
Explanation:
it makes sense
Answer:
W = 166.35 KJ
Explanation:
P₁ = 600 KPa
V₁ = 0.4 m³
V₂ = 0.2 m³
T = 300 K
W = ?
We can find the solution from the standard relation for work in an isothermal process
W = -n*R*T*Ln (Vf / Vi)
We know that
n*R*T = P*V ⇒ P₁*V₁ = P₂*V₂ = n*R*T = 600 *0.4 = 240
Now, we use the equation
W = -n*R*T*Ln (Vf / Vi) = - P₁*V₁*Ln (Vf / Vi)
⇒ W = -240*Ln (0.2 / 0.4) = 166.35 KJ
