Answer:
They are able to balance torques due to gravity.

Explanation:
When two friends of different masses will balance themselves on see saw then at equilibrium position the see saw will remain horizontal
This condition will be torque equilibrium position where the see saw will not rotate
Here we can say

here we know that force is due to weight of two friends
and their positions are different with respect to the lever about which see saw is rotating
since both friends are of different weight so they will balance themselves are different positions as per above equation
They are formed from erosion and weathering.
It's 60.... i have used the formula
L=r^2mw
and didn't use the value 0.75...
200 N, that is if the force is balanced and the wall doesn't move
Answer:
2 m/s and -2 m/s
Explanation:
The object travels with an angle of
60.0°
with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).
If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:
