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3 years ago

How far does a car in 90 sec if it is traveling at a speed of 55m/s show equation

Physics

1 answer:

Mkey [24]3 years ago

5 0

Answer:

4950 meters

Explanation:

Recall that the formula for the speed (v) is given by the quotient of the distance traveled (d) divided by the time (t) it took to cover that distance:

$v=\frac{d}{t}$

Therefore, for this case in which the car travels at 55 m/s for 90 seconds, we can replace these values in the formula, and solve for the distance covered:

$v =\frac{d}{t} \\55 \frac{m}{s} =\frac{d}{90\,s} \\d=55*90 m\\\\d=4950\,m$

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2 years ago

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3 years ago

A bat moving at 3.7 m/s is chasing a ying insect. The bat emits a 36 kHz chirp and receives back an echo at 36.79 kHz. At what s

3241004551 [841]

Answer:

The speed the bat is gaining on its prey is 0.03m/s

Explanation:

Given;

speed of the bat, v₀ = 3.7 m/s

frequency of the bat, F₀ = 36 kHz

frequency of the source, Fs = 36.79

This is relative motion between a source of the sound and the observer. The phenomenon is known as Doppler effect.

Apply the following equation to determine the speed of the insect which is the source;

$F_0 = F_s[\frac{v+v_0}{v-v_s} ]\\\\\frac{F_0}{F_s} = [\frac{v+v_0}{v-v_s} ]\\\\\frac{36.79}{36} = \frac{340+3.7}{340-v_s}\\\\1.0219 = \frac{343.7}{340-v_s}\\\\ 340-v_s = \frac{343.7}{1.0219}\\\\340-v_s = 336.33\\\\v_s = 340-336.33\\\\v_s = 3.67 \ m/s$

The speed the bat is gaining on its prey = 3.7m/s - 3.67m/s = 0.03 m/s

Therefore, the speed the bat is gaining on its prey is 0.03m/s

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2 years ago