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prohojiy [21]
3 years ago
5

9. What is the uncertainty of the measurement of a voltage measurement on the oscilloscope when the vertical scale is set to 2V

/ division, given that it uses an 8-bit D/A converter?
Physics
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

Accuracy of measurement = ± 0.19%

Explanation:

For a 8-bit D/A converter,

Accuracy of measurement = 1/2ⁿ = 1/2⁸ = 1/256 = 0.0039 = 0.39% or ± 0.19%

Given that vertical scale is set to 2V/division so the absolute value of the error is 2*0.0019 = ± 3.8 mV

Example:

In a digital oscilloscope, 1 volt/division means that each division on the oscilloscope shows exactly 1 volt, similarly, 0.5 V/division means that each division shows exactly 0.5 volt so 1 V will take 2 divisions hence the signal will appear larger (zoomed in) on the other hand, setting it on 2V/division will make the signal appear smaller (zoomed out).

Note: Volts/division doesn't change the amplitude of the signals, it only makes them appear zoomed in or out so that the required signal can fit on the oscilloscope screen.

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All rules to find work in changing force in physics ​
saw5 [17]

Answer:

FORCE - rate of change of momentum, ie its changing velocity [change in velocity is of more concern] NEWTON

WORK - product of force and displacement, ie [velocity may be constant or variable but change in position with certain force is of more concern] JOULES

I hope you understood from this..

7 0
2 years ago
What is the velocity of a wave with a frequency of 45 Hertz and a wavelength of 3 meters?
Juli2301 [7.4K]

Explanation:

By using v=( f )x( lambda )

v= 45 s^-1 x 3 m

Therefore v = 135 ms^-1

8 0
3 years ago
How much work is required to compress 5.05 mol of air at 19.5°C and 1.00 atm to one-eleventh of the original volume by an isothe
Rus_ich [418]

Explanation:

(a)  For an isothermal process, work done is represented as follows.

             W = -nRT ln(\frac{V_{2}}{V_{1}})

Putting the given values into the above formula as follows.

        W = -nRT ln(\frac{V_{2}}{V_{1}})

             = - 5.05 mol \times 8.314 J/mol K \times (19.5 + 273) K \times ln (\frac{\frac{V_{1}}{11}}{V_{1}})

             = -12280.82 \times ln (0.09)

             = -12280.82 \times -2.41

             = 29596.78 J

or,         = 29.596 kJ       (as 1 kJ = 1000 J)

Therefore, the required work is 29.596 kJ.

(b) For an adiabatic process, work done is as follows.

         W = \frac{P_{1}V^{\gamma}_{1}(V^{1-\gamma}_{2} - V(1-\gamma)_{1})}{(1 - \gamma)}

              = \frac{-nRT_{1}(11^{\gamma - 1} - 1)}{1 - \gamma}

              = \frac{-5.05 \times 8.314 J/mol K \times 292.5 (11^{1.4 - 1} - 1)}{1 - 1.4}

              = 49.41 kJ

Therefore, work required to produce the same compression in an adiabatic process is 49.41 kJ.

(c)   We know that for an isothermal process,

               P_{1}V_{1} = P_{2}V_{2}

or,       P_{2} = \frac{P_{1}V_{1}}{V_{2}}

                    = 1 atm (\frac{V_{1}}{\frac{V_{1}}{11}})

                    = 11 atm

Hence, the required pressure is 11 atm.

(d)   For adiabatic process,  

          P_{1}V^{\gamma}_{1} = P_{2}V^{\gamma}_{2}

or,       P_{2} = P_{1} (\frac{V_{1}}{V_{2}})^{1.4}

                    = 1 atm (\frac{V_{1}}{\frac{V_{1}}{11}})^{1.4}

                    = 28.7 atm

Therefore, required pressure is 28.7 atm.

6 0
4 years ago
Alguien me puede ayudar con esa tabla ​
Scilla [17]
私は英語がわかりません sorry pls translate
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3 years ago
How can you justifies the age of earth being 4.5 billion years old
IceJOKER [234]

Answer:

ummmmmmmmmm through science??

8 0
3 years ago
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