Answer:
Explanation:
Hello,
In this case, we use the ideal gas equation to compute the volume as shown below:
Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:
Thus, we compute the volume with the proper ideal gas constant, R:
Best regards.
Answer: Volume of 1g of pure gold
Given;
Density of a pure gold=19.3
Mass of a pure gold =1g
To find:
Volume of 1g of pure gold
Solution:
According to the formula,
Density= Mass/Volume
Where =density of pure gold
m=mass of pure gold
v=volume of pure gold
From the above equation volume can be calculated as
Substitute the values of mass and density value in the above equation
Result:
Thus the volume of 1g of pure gold is