The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms
<h3>Avogadro's hypothesis </h3>
1 mole of Mg = 6.02×10²³ atoms
<h3>How to determine the atoms in 0.58 mole of Mg </h3>
1 mole of Mg = 6.02×10²³ atoms
Therefore,
0.58 mole of Mg = 0.58 × 6.02×10²³
0.58 mole of Mg = 3.49×10²³ atoms
Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg
Learn more about Avogadro's number:
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Answer:
0.67mol/Kg
Explanation:
The following were obtained from the question:
Mole of solute = 0.50mol
Mass of solvent = 750g = 750/1000 = 0.75Kg
Molality =?
Molality = mole of solute /mass of solvent
Molality = 0.5/0.75
Molality = 0.67mol/Kg
Answer:
Ununoctium
Explanation:
It's at the very end of the periodic table
Answer:
The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons. ... The value of the radius may depend on the atom's state and context.
Explanation:
Answer:
Cation
Explanation:
Since the protons are greater than electrons, this means the atom has a net positive charge on it and is now called a cation.
As there are 4 protons, this means that the outermost shell has 2 valence electrons 2s1, 2s2 and this is Group 2 element. Looking at Periodic table, we find that this is beryllium 4Be5 and is denoted as Be^2+
