Answer: -
The concentration is 0.91 mol/ L
Explanation: -
The osmotic pressure = 23 atm
Absolute temperature = 309 K
Universal gas constant = 0.08206 L atm mol⁻¹ K⁻¹
We know the formula
Osmotic pressure = molar concentration x universal gas constant x absolute temperature
Plugging in the values
23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K
Molar concentration =
mol/ L
= 0.91 mol / L
We can calculate for temperature by assuming the equation
for ideal gas law:
P V = n R T
Where,
P = pressure = 1.80 atm
V = volume = 18.2 L
n = number of moles = 1.20 moles
R = gas constant = 0.08205746 L atm / mol K
Substituting to the given equation:
T = P V / n R
T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm /
mol K)
T = 332.70 K
We can convert K unit to ˚C unit by subtracting 273.15
to Kelvin, therefore
T = 59.55 ˚<span>C</span>
what grade is this because apparently i like to know what grade it is before i solve it
Explanation:
The second quantum number also called the orbital quantum number describes the type of orbital or shape of it.
Answer: D. The specific orbital within a sublevel.