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jeka57 [31]
4 years ago
7

Identify the major ionic species present in an aqueous solution of K2SO4.

Chemistry
2 answers:
notsponge [240]4 years ago
6 0

Answer:

SO42-

Explanation:

in water solution, salt potassium sulfate dissociates into

potassium (K+) and sulfate (SO4- -) ions. The potassium ions

each have a charge of +1, and the sulfate ions have a charge of -2.

mariarad [96]4 years ago
6 0

Answer:

The two major ionic species present in an aques solution of K2SO4 is

2K+ and SO42-

Explanation:

During the dissoiation  K2SO4 produce two ionic forms namely cation and anion

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<span>So basically since this is a balanced equation, the ratios of mols of the elements are equal, atom wise. </span>

<span>So you notice they give you Br2 is 1.0 kg (1000g) and that means there are 2 mols of Br2. And its asking for Cl2, (on the left) it also has 2 mols. </span>
<span>Then you can start from 1000g Br2 and multiply with 2 mol Br2 and 159.8g Br2 on the bottom. The 159 8 is the actual grams per mol. Then when you write this down, continue multipying with the next fraction. </span>

<span>Since you know the molar mass of Cl2 is 70.4 and you know theres 2 mols, you can say that 2 mols of Br2 = 2 mols of Cl2 so you should be able to multiple 2 mol Br2 / 159.8g Br2 with 70.4 g Cl2 / 2 mol Cl2. Bam the mols cancel out and you have the grams for Cl2. Multiple all that out and you should get 443g Cl2. Notice how the beginning question gives 2 significant figures, so technically 440g Cl2 is more of an exact number.</span>
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