Answer:
1. 2160 J
2. 2940 J
3. 64 J
Explanation:
1. Determination of the work done.
Weight (W) = 180 N
Height (h) = 12 m
Workdone =?
Wd = W × h
Wd = 180 × 12
Wd = 2160 J
Thus, the Workdone is 2160 J
2. Determination of the work done.
Mass (m) = 50 Kg
Height (h) = 6 m
Acceleration due to gravity (g) = 9.8 m/s²
Workdone =?
Wd = mgh
Wd = 50 × 9.8 × 6
Wd = 2940 J
Thus, the Workdone is 2940 J
3. Determination of the work done.
Force (F) = 16 N
Distance (d) = 4 m
Workdone =?
Wd = F × d
Wd = 16 × 4
Wd = 64 J
Thus, the Workdone is 64 J
Answer:
a) t = 4.5 s
, b) x = 81 m
Explanation:
a) For this problem we will use kinematic relationships
For the car
x = v₀ t + ½ a₁ t²
Since the car kicks from rest, the initial speed is zero
x = ½ a₁ t²
For the bus
v₂ = x / t
x = v₂ t
At the point where they are located it has the same position, so we can match the equation
½ a₁1 t² = v₂ t
½ a₁ t = v₂
t = 2 v₂ / a₁
Let's calculate
t = 2 18 /8.0
t = 4.5 s
b) to find the position
x = v₂ t
x = 18 4.5
x = 81 m
Answer:
Explanation:
1) No take-off possible
2) The downward force is greater than the upward force.
3) 2000 + 950 = 2950 N upward
Answer:
25km/h
Explanation:
This is a trick question, the average speed in this case does not really depend on calculation or extrapolation, it just refers to an event that is yet to occur,
In other words, if you want to achieve an average speed of 25km/h for 23km, then you should drive your car at a constant speed of 25km/h, any variation in speed may cause a change in your average speed at the end.