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kolezko [41]
3 years ago
13

Which of the following is the most likely cause for the increase in pressure observed in the container as the reaction reaches e

quilibrium?
a) a decrease in the strength of intermolecular attractions among molecules in the flask
b) an increase in the strength of intermolecular attractions among molecules in the flask
c) an increase in the number of molecules, which increase the frequency of collisions with the walls of the container
d) an increase in the speed of the molecules than then collide with the walls of the container with greater force
Chemistry
1 answer:
ryzh [129]3 years ago
6 0

Answer:

c) an increase in the number of molecules, which increase the frequency of collisions with the walls of the container.

Explanation:

Hello!

When in a chemical reaction the amount of mole of products is greater than the amount of mole of reagents, an increase in pressure is observed upon reaching equilibrium.

Increases in temperature can also produce an increase in pressure although in some cases an increase in temperature may occur under isobar conditions (constant pressure).

Successes with your homework!

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Hydrofluoric acid (HF) can be prepared according to the following equation:
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Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.

For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

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3 years ago
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Sodium chlorate = sodium chloride + oxygen formula
UNO [17]

Answer:

NaClO3 = NaCl + O2

Explanation:

Word equation: Sodium chlorate → Sodium chloride + Oxygen gas

6 0
2 years ago
What did the professer use a catalyst for the flubber experiment
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Thank you for posting your question here at brainly. I hope the answer helps.
7 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

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3 years ago
What is gold atomic number
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Answer:

79

Explanation:

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