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3 years ago

Lucia wants to change the motion map shown so that it shows uniform circular motion.

2 answers:

7 0

This is all related to the centripetal force. Rememeber that In uniform circular motion, velocity changes due to change in direction, eventhough magnitude remains constant. having that in mind we know that <span>She should change the direction of the vectors that are toward the center of the circle so that each points away from the center of the circle.</span>

melamori03 [73]3 years ago

3 0

Just took the test. It's D. She should change the lengths of the vectors that point toward the center so that each is the same length.

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A Decay Chain

Strike441 [17]

Answer : The energy released in first step of thorium-232 decay chain is $7.974\times 10^{-13}J$

Explanation :

First we have to calculate the mass defect $(\Delta m)$ .

The balanced reaction is,

$^{232}Th\rightarrow ^{228}Ra+^{4}He$

Mass defect = Sum of mass of product - sum of mass of reactants

$\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})$

$\Delta m=(228.0301069+4.002602)-(232.038054)=5.34\times 10^{-3}amu=8.86\times 10^{-30}kg$

conversion used : $(1amu=1.66\times 10^{-27}kg)$

Now we have to calculate the energy released.

$Energy=\Delta m\times (c)^2$

$Energy=(8.86\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$Energy=7.974\times 10^{-13}J$

The energy released is $7.974\times 10^{-13}J$

Therefore, the energy released in first step of thorium-232 decay chain is $7.974\times 10^{-13}J$

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