Answer:
five half lives
Explanation:
Half-life is the time required for a quantity to reduce to half of its initial value.
How many half lives it would take to reach 3.13% form 100% of it's initial concentration:
100% - 50% : First Half life
50% - 25%: Second Half life
25% - 12.5%: Third Half life
12.5% - 6.25%: Fourth Half life
6.25% - 3.125%: Fifth Half life
This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.
The main class of high-temperature superconductors are in the class of copper oxides (only some particular copper oxides) especially the Rare-earth barium copper oxides (REBCOs) such as Yttrium barium copper oxide (YBCO).
<h3>What superconducting material works with the highest temperature?</h3>
As of 2020, the material with the highest accepted superconducting temperature is an extremely pressurized carbonaceous sulfur hydride with a critical transition temperature of +15°C at 267 GPa.
<h3>How do high-temperature superconductors work?</h3>
High-temperature superconductivity, the ability of certain materials to conduct electricity with zero electrical resistance at temperatures above the boiling point of liquid nitrogen, was unexpectedly discovered in copper oxide (cuprate) materials in 1987.
Learn more about high temperature superconductors here:
<h3>
brainly.com/question/1657823</h3><h3 /><h3>#SPJ4</h3>
Answer:
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Explanation:
Concentration of lead nitarte = ![[Pb(NO_3)_2]=0.010 M](https://tex.z-dn.net/?f=%5BPb%28NO_3%29_2%5D%3D0.010%20M)

1 Mole of lead nirate gives 1 mole of lead ion.
Concentration of lead ion in the solution = 

Concentration of chloride ions = ![[Cl^-]](https://tex.z-dn.net/?f=%5BCl%5E-%5D)
The value of ![K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20for%20%5Btex%5DPbCl_2%3D%201.6%5Ctimes%2010%5E%7B-5%7D)
![K_{sp}=[Pb^{2+}][Cl^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E2)
![1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-5%7D%3D0.010%20M%5Ctimes%20%5BCl%5E%7B-%7D%5D%5E2)
![[Cl^-]=0.04 M](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D0.04%20M)
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Answer:

Explanation:
Hello!
In this case, considering the Avogadro's number, which relates the number of particles and one mole, we can infer that 1 mole of any element contains 6.022x10²³ atoms as shown below:

Thus, we compute the number of atoms in 0.035 moles as shown below:

Best regards!
Explanation:
b. Bromo cyclopentane + HBr