Answer:
c = 4
Explanation:
From work-energy theorem KE = workdone.
Given F = (cx - 3.00x²)i
W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A
W = cx²/2 –x³ + A
Where A is a constant
At x = 0, KE = 20J
So W = 20J at x = 0
20 = c×0 - 0 +A
A = 20
So W = cx²/2 –x³ + 20
Also when x = 3.00m, W = KE = 11J
So
11 = c×3²/2 – 3³ + 20
11 = 4.5c – 7
4.5c = 11 + 7
4.5c = 18
c = 18/4.5 = 4
c = 4
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. ... In reaction, a thrusting force is produced in the opposite direction.
Explanation:
In the exosphere, there is thin air, since it is the uppermost level in the atmosphere. It is made mostly of helium and hydrogen. But, traces of other gases such as atomic oxygen and carbon dioxide can also be found in the exosphere.
Use a scale and record the weight in cm^3
