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3 years ago

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before a collision, a 25 kg object is moving to the right at 12 m/s. Find the impulse acted on the object if, after the collisio

n, the object moves to the left at 6.2 m/s

1 answer:

lutik1710 [3]3 years ago

3 0

Answer:

455 kg m/s

Explanation:

The impulse acted on the object is equal to the change in momentum of the object:

$I=\Delta p$

and the change in momentum is equal to the product between the mass of the object and the change in velocity:

$\Delta p=m \Delta v=m (v-u)$

where:

m = 25 kg is the mass of the object

u = 12 m/s is the initial velocity of the object

v = -6.2 m/s is the final velocity of the object (we have taken a negative sign because the object now moves in the opposite direction)

Therefore, the impulse is

$I=\Delta p=m(v-u)=(25 kg)(12 m/s-(-6.2 m/s))=455 kg m/s$

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<u>Accelerated Motion </u>

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Explanation-

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3 years ago