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Softa [21]
3 years ago
6

How does the​ long-run equilibrium for a monopolistically competitive market differ from the​ long-run equilibrium for a perfect

ly competitive​ market?
Physics
1 answer:
Katen [24]3 years ago
3 0

Answer and Explanation:

The main difference between monopolistic competition and perfect competitive market are given bellow

Excess capacity : There is constantly an overabundance limit in monopolistic challenge and not in the ideal challenge. Over the long haul, superbly aggressive firms produce at the proficient scale,where as monopolistically focused firms produce beneath this level. Firms are said to have abundance limit under monopolistic challenge. As it were, a monopolistically focused firm, in contrast to a splendidly aggressive firm, could build the amount it delivers and lower the normal all out expense of generation.

Markup over marginal cost:   the another distinction between flawless challenge and monopolistic challenge is the connection among cost and minor expense. At an aggressive firm consistently cost equivalents negligible expense. Where as, in monopolistically aggressive firm, cost surpasses minimal expense becouse the firm consistently have some market control.

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A) a balance

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4 years ago
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What is the magnitude of the force required to stretch a 20 cm-long spring, with a spring constant of 100 N/m, to a length of 21
GalinKa [24]

The correct answer to the question is: 1 N.

EXPLANATION:

As per the question, the spring constant or the force constant of the spring is given as k = 100 N/m.

The original length of the spring L = 20 cm.

The stretched length of the spring L'= 21 cm.

Hence, the change in length will be-

                              ∆L = L' - L

                                    = 21 cm - 20 cm

                                    = 1 cm

                                    = 0.01 m

We are asked to calculate the magnitude of force acting on the spring .

From Hooke's  law, we know that the restoring force that acts on the spring is proportional to the distance .

Mathematically it can be written as -

                F = - kx.

Here, k is the force constant.

         x is the change in length due to compression or elongation.

The negative sign is due to the fact that it is opposite to the applied force.


Hence, the applied force on the spring is calculated as -

            F = kx

               = k × ∆L

               = 100 N/ m × 0.01 m

               = 1 N.

Hence, the force acting on the spring is 1 N.


                                                   

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