Answer:
Explanation:
Usually office's networks works using the TCP/IP protocol, this mean that each workstation has an assigned IP. This IP are the directions gave to each computer on the network,
This IP are usually asigned by a DHCP Server. Servers every time a new device connect to the Network, assigns to it an IP, this way every Computer will know how to send or request information from that Computer.
In the TCP/IP protocol is not posibble for two computer to have the same IP. This causes what it call IP Conflict, IP Conflict make imposible the comunications between those devices and the Network.
On Power outages all the Computer are turn off, because of this they disconnect from the Network and need to requests IP one more time to gain comunication,
We this in mind, we can predict that frequent power outages can cause for all the Computer in the Network to request new IPs very frequently this will cause IP Conflict in several units, disconnecting them from the network and making them no longer able to find files on the network. To fix this, what can be done it to establish Static IP to every workstation, this way we they request a new IP, the DHCP Serve will assign them the same IP form every session.
This way, the IP Conficlt can end. Another option is to make the DHCP to assign new IP to every unit one more time, eliminating the machines with same IP.
Answer: a) E= 6.63x10^-19J
E= 3.97×10^2KJ/mol
b) E = 3.31×10^-19J
E= 18.8×10^4 KJ/mol
C) E = 1.32×10^-33J
E= 8.01×10^-10KJ/mol
Explanation:
a) E = h ×f
h= planks constant= 6.626×10^-34
E=(6.626×10^-34)×(1.0×10^15)
E=6.63×10^-19J
1mole =6.02×10^23
E=( 6.63×10^-19)×(6.02×10^23)
E=3.97×10^2KJ/mol
b) E =(6.626×10^-34)/(1.0×10^15)
E=3.13×10^-19J
E= 3.13×10^-19) ×(6.02×10^23)
E= 18.8×10^3KJ/MOL
c) E= (6.626×10^-34) /0.5
E= 1.33×10^-33J
E= (1.33×10^-33) ×(6.02×10^23)
E= 8.01×10^-10KJ/mol
C ,A ,B ,D
I think I’m to sure
100N describes the weight of the sandbag, while 100kg is the mass of the sandbag.
To calculate acceleration, divide your weight by the mass, thus the accleration is:
Both options 5 and 6
Explanation:
Let us consider option 5,
In option 5 body is moving up with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.
Let us consider option 6,
In option 6 body is moving down with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.
