Answer:
35 kilogram per stair will weight
Answer:
FJ = 31.48N
Explanation:
In this case you have that the torque exerted by each, thumb and finger, over the point P, is equal and opposite by the torque exerted by each Jaw.
You equal one of the torque produced by your hand, as for example, the torque of the finger, with the torque produced by one jaw:
(1)
FF: finger force = 10.0N
FJ: jaw force = ?
d1: distance from finger to point P = 8.50cm = 0.085m
d2: distance form the border of the Jaws to the point P = 2.70cm = 0.027m
You solve the equation (1) for FJ and replace the values of the other parameters:
The force exerted by each jaw is 31.48N
Answer:
It is a change in velocity over a period of time.
Explanation:
- It is measured in metres/second2<em><u> </u></em><em><u>u</u></em><em><u>s</u></em><em><u>i</u></em><em><u>n</u></em><em><u>g</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u> </u></em><em><u> </u></em><em><u>accelerometer</u></em><em><u>.</u></em>
Answer:
(a) the force is 8.876 N
(b) the magnitude of each charge is 4.085 μC
Explanation:
Part (a)
Given;
coulomb's constant, K = 8.99 x 10⁹ N.m²/C²
distance between two charges, r = 10 cm = 0.1 m
force between the two charges, F = 15 N
when the distance between the charges changes to 13 cm (0.13 m)
force between the two charges, F = ?
Apply Coulomb's law;
Part (b)
the magnitude of each charge, if they have equal magnitude
where;
F is the force between the charges
K is Coulomb's constant
Q is the charge
r is the distance between the charges
Answer:
326.4 mC
Explanation:
The relationship between charge, capacitance and voltage in a capacitor is given by
where
C is the capacitance
Q is the charge
V is the voltage
In this problem, we have
C = 34 mF is the capacitance
V = 9.6 V is the voltage
Re-arranging the equation and substituting the numbers, we find the charge stored in the capacitor: