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3 years ago

The hight A note on the piano has a wavelength of 0.0487 m what’s the frequency ?

Physics

1 answer:

Brrunno [24]3 years ago

4 0

Answer:

A modern piano has 88 keys and is tuned to twelve-tone equal temperament. It has its 49th key, the fifth A, also called A4, tuned to a frequency of 440 Hz (referred to as A440).

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The __________ lobe contains the area of the cortex involved in auditory processing called the primary __________ cortex. A. par

Vlada [557]

The temporal lobe contains the area of the cortex involved in auditory processing called the primary auditory cortex.

The temporal lobe is associated with auditory processing and olfaction.
The primary auditory cortex is the part of the temporal lobe which processes auditory information.

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2 years ago

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which of the following small bodies are the hardest to tell apart because they are made of similar materials ? A . dwarf planets

grandymaker [24]

Option D is right that is asteroids and meteroids.

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3 years ago

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Calcular la longitud del faldón de una Rampa de Acceso , que en planta tiene una longitud de 20 m y la pendiente es 27%.

seraphim [82]

La longitud del faldón de la rampa es de 5.4 m.

La pendiente expresada en porcentaje sigue la siguiente ecuación:

$m=\frac{y}{x}*100$ (1)

Donde:

y es la elevacion de la rampa (faldón)
x es la longitud de la ramapa (20 m)

Sabemos que la pendiente es de 27%. Por lo tanto, usando la ecuación 1, despejamos y.

$27=\frac{y}{20}*100$

$y=\frac{27*20}{100}$

$y=5.4\: m$

La longitud del faldón es 5.4 m

Pudes ver más sobre el tema aquí:

brainly.com/question/8906330

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2 years ago

CAN SOMEONE HELP ME PLEASE ASAP

Lady_Fox [76]

The third choice is correct

8 0

3 years ago

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The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.180 × 10-3 m3. Into this cavity is placed 1.100 × 10-

nikdorinn [45]

Answer:

The answer is " $60.74^{\circ}$ ".

Explanation:

Cavity and benzene should be extended in equal quantities.

$\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\$

$\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\$

$\to \Delta T = \frac{0.072}{0.001185328 }\\\\ \to \Delta T = 60.74^{\circ}\\$

5 0

2 years ago