Answer:
Part a)
Part b)
Explanation:
As we know that by parallel axis theorem we will have
Part a)
here we know that for a stick the moment of inertia for an axis passing through its COM is given as
now if we need to find the inertia from its end then we will have
Part b)
here we know that for a cube the moment of inertia for an axis passing through its COM is given as
now if we need to find the inertia about an axis passing through its edge
Answer:
The minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m
Explanation:
We know by equation of motion that,
Where, v= final velocity m/sec
u=initial velocity m/sec
a=Acceleration m/
s= Distance traveled before stop m
Case 1
u= 13 m/sec, v=0, s= 57.46 m, a=?
a = -1.47 m/ (a is negative since final velocity is less then initial velocity)
Case 2
u=29 m/sec, v=0, s= ?, a=-1.47 m/ (since same friction force is applied)
s = 285.94 m
Hence the minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m
Answer:
C.) 1.5 kg
Explanation:
Start with the equation:
Plug in what you know, and solve:
Find matching soluation:
C.) 1.5 kg