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Andrei [34K]
4 years ago
10

After digging deeper and deeper, you would eventually hit solid

Physics
2 answers:
Slav-nsk [51]4 years ago
8 0

Answer:

the answer is bedrock

Explanation:

Hope this helps : )

Gekata [30.6K]4 years ago
6 0

Answer:

Bedrock

Explanation: hope i h

elped

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A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acc
Paha777 [63]
The magnitude of the acceleration of the runner is given by:
a= \frac{v_f-v_i}{t}
where
v_f=8.0 m/s is the final speed of the runner
v_i=0 is the initial speed of the runner
t=4.0 s is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2
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4 years ago
What is the person’s displacement for the trip?<br><br> what is a vector quantity? give an example.
borishaifa [10]

Answer:

+ 3.0 m

Explanation:

displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m

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3 years ago
A student wearing in-line skates pushes against a brick wall. why does the student move away from the wall ?
Alex

Answer:

Because the forces acting on the student are creating a net force.

Explanation:

I took the test and that was the answer

7 0
3 years ago
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Which best compares and contrasts Banking and Investment Planning?
valina [46]

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Its C i think

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3 years ago
I am desperate to get to Denver, Colorado to catch the Denver Broncos
Pavlova-9 [17]

Answer:

<em>The average speed needed is 68.4 mi/h</em>

Explanation:

<u>Average Speed </u>

If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:

\displaystyle V=\frac{d}{t}

The distance to get to Denver from the Hamilton Street Campus is d=1,778 miles. An estimated time of t=26 hours should be needed to cover that distance, thus you will need to travel at an average speed of:

\displaystyle V=\frac{1,778\ mi}{26\ h}

V = 68.4 mi/h

The average speed needed is 68.4 mi/h

6 0
3 years ago
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