Answer:
Ka= 2.3 x 10^-11
Explanation:
so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius
plugging in Kb and Kw, we have
Ka x 4.4 x 10^-4 = 10^-14
solving for Ka,
Ka= (10^-14)/(4.4 x 10^-4)
Ka= 2.3 x 10^-11
M1V1 = M2V2
225M1 = (2)(120)
225M1 = 240
M1 = 240/225 = 1.066 M C
Answer:
Explanation:
The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:
ΔG = -RT ln K
<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>
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Replacing (110kJ = 110000J):
110000J/mol = -8.314J/molK*303.15K ln K
-43.644 = lnK
1.11x10⁻¹⁹ = K
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The atomic number,atomic mass,valence electrons and the formula for calculating the number of neutrons is also given.The following table has been completed below in the attachment.
Explanation:
Atomic Number:the number of protons /electrons present in the nucleus of an atom is called the atomic number.
Mass Number/Atomic Mass:the number of protons and neutrons present in a nucleus
<u>Example:</u>;here;6 implies the atomic number and 12 implies the mass number/atomic mass
<u><em>No.of neutrons=Mass number-Number of protons</em></u>
Valence electrons:the number of electrons present in the outer most shell of an atom are called valence electrons
<u>Example:</u>If we consider a carbon atom;as its <em>e</em><em>lectronic configuration is2,4 and</em> it belongs to 4th group.Therefore the number of valency electrons in carbon is <u>4.</u>
I think the answer is b because that is true