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3 years ago

What characteristic distinguishes a meteorite from a terrestrial rock?

Physics

1 answer:

alisha [4.7K]3 years ago

8 0

Answer:

(I) meteorite is usually covered with a dark crust from burning in Earth's atmosphere.

(II) A meteorite usually has a high metal content.

(III) Meteorites when compared to terrestrial rocks have different isotope ratios of particular elements.

(IV) Meteorites contain rare elements, such as iridium, that terrestrial rocks do not contain.

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The fact that light travels at 300,000 km/s is a consequence of

Tresset [83]

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The particle that move with that kind of speed creates energy way faster than the particle that don't. Which means that it would require less effort to produce the energy,</span>

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4 years ago

What are the parts of an atom

Ivenika [448]

Number three

They contain protons (positive), neutrons (negative), electrons (neutral) and all are in a nucleus which is part of an atom

7 0

3 years ago

Read 2 more answers

which of the four terms below includes the other three terms (1)community (2)ecosystem (3)population (4)individuala

Brut [27]

I think the answer is 3, population.

7 0

4 years ago

3. The circuit below shows two outdoor lights, run by a battery. Four amps of

miv72 [106K]

Answer:

The answer to your question is given below.

Explanation:

From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.

This can further be understood if we determine the current flowing through each bulb. This is illustrated below:

Voltage (V) = 30V

Resistant 1 (R1) = 15Ω

Current 1 (I1) =..?

V = I1R1

30 = I1 x 15

Divide both side by 15

I1 = 30/15

I1 = 2A.

Voltage (V) = 30V

Resistant 2 (R2) = 15Ω

Current 2 (I2) =..?

V = I2R2

30 = I2 x 15

Divide both side by 15

I2 = 30/15

I2 = 2A.

The overall current(I) in the circuit:

I = I1 + I2

I = 2 + 2 = 4A.

From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts

4 0

4 years ago

You would like to store 8.1 J of energy in the magnetic field of a solenoid. The solenoid has 620 circular turns of diameter 6.6

marta [7]

Answer:

(a) The current needed is 56.92 A

(b) The magnitude of the magnetic field inside the solenoid is 0.134 T

Explanation:

Given;

energy stored in the magnetic field of solenoid, E = 8.1 J

number of turns of the solenoid, N = 620 turns

diameter of the solenoid, D = 6.6 cm = 0.066 m

radius of the solenoid, r = D/2 = 0.033 m

length of the solenoid, L = 33 cm = 0.33 m

Inductance of the solenoid is given as;

$L= \frac{\mu_o N^2 A}{l}$

where;

A is the area of the solenoid = πr² = π (0.033)² = 0.00342 m²

μ₀ is permeability of free space = 4π x 10⁻⁷ H/m

$L= \frac{4\pi*10^{-7} *620^2 *0.00342}{0.33} \\\\L = 0.005 \ H$

(A). How much current needed

Energy stored in magnetic field of solenoid is given as;

$E = \frac{1}{2} LI^2\\\\$

Where;

I is the current in the solenoid

$E = \frac{1}{2} LI^2\\\\I^2 = \frac{2E}{L}\\\\I = \sqrt{\frac{2*8.1}{0.005}}\\\\ I = 56.92 \ A$

(B) The magnitude of the magnetic field inside the solenoid

B = μ₀nI

where;

n is number of turns per unit length

B = μ₀(N/L)I

B = (4π x 10⁻⁷)(620/0.33)(56.92)

B = 0.134 T

$U_B = \frac{B^2}{2\mu_0} \\\\U_B = \frac{(0.134)^2}{2*4\pi*10^{-7}} \\\\U_B = 7143.54 \ J/m^3\\\\U_B = 7.144 \ kJ/m^3$

3 0

3 years ago