Answer:
The y-component of the electric force on this charge is ![F_y = -1.144\times 10^{-6}\ N.](https://tex.z-dn.net/?f=F_y%20%3D%20-1.144%5Ctimes%2010%5E%7B-6%7D%5C%20N.)
Explanation:
<u>Given:</u>
- Electric field in the region,
![\vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.](https://tex.z-dn.net/?f=%5Cvec%20E%20%3D%20%28148.0%5C%20%5Chat%20i-110.0%5C%20%5Chat%20j%29%5C%20N%2FC.)
- Charge placed into the region,
![q = 10.4\ nC = 10.4\times 10^{-9}\ C.](https://tex.z-dn.net/?f=q%20%3D%2010.4%5C%20nC%20%3D%2010.4%5Ctimes%2010%5E%7B-9%7D%5C%20C.)
where,
are the unit vectors along the positive x and y axes respectively.
The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,
![\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.](https://tex.z-dn.net/?f=%5Cvec%20E%20%3D%20%5Cdfrac%7B%5Cvec%20F%7D%7Bq%7D%5C%5C%5Ctherefore%20%5Cvec%20F%20%3D%20q%5Cvec%20E%5C%5C%3D%2810.4%5Ctimes%2010%5E%7B-9%7D%29%5Ctimes%20%28148.0%5C%20%5Chat%20i-110.0%5C%20%5Chat%20j%29%5C%5C%3D%281.539%5Ctimes%2010%5E%7B-6%7D%5C%20%5Chat%20i-1.144%5Ctimes%2010%5E%7B-6%7D%5C%20%5Chat%20j%29%5C%20N.)
Thus, the y-component of the electric force on this charge is ![F_y = -1.144\times 10^{-6}\ N.](https://tex.z-dn.net/?f=F_y%20%3D%20-1.144%5Ctimes%2010%5E%7B-6%7D%5C%20N.)
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Answer:
Bent knees
Explanation:
Depending the height your jumping from, if you were jumping from a high structure it's best if you jump and land on knees so you dont sprang your ankles from jumping and landing on your straight legs, you could even pull a muscle if you land on straight legs.
Time should not be messed with
for bad things could happen
so think before you act or you'll regret it
Insomnia and night terrors