Answer:
v = -v₀ / 2
Explanation:
For this exercise let's use kinematics relations.
Let's use the initial conditions to find the acceleration of the electron
v² = v₀² - 2a y
when the initial velocity is vo it reaches just the negative plate so v = 0
a = v₀² / 2y
now they tell us that the initial velocity is half
v’² = v₀’² - 2 a y’
v₀ ’= v₀ / 2
at the point where turn v = 0
0 = v₀² /4 - 2 a y '
v₀² /4 = 2 (v₀² / 2y) y’
y = 4 y'
y ’= y / 4
We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.
v² = v₀² -2a y’
v² = 0 - 2 (v₀² / 2y) y / 4
v² = -v₀² / 4
v = -v₀ / 2
We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.
Answer:
Car 2 is travelling in a much higher speed than Car 1.But they are travelling or meeting in the same acceleration
Explanation:
Fgravity = G*(mass1*mass2)/D²
G is the gravitational constant throughout the universe.
D is the distance between both objects.
D is now reduced by a factor of 5, meaning Dnew = D/5 we get
Fgravitynew = G*(mass1*mass2)/(D/5)² =
= G*(mass1*mass2)/(D²/25) =
= 25* G*(mass1*mass2)/D² = 25* Fgravity
the new force of gravity/attraction is 25×16 = 400 units.
Gamma rays have the highest energies and the shortest wavelengths.
