An isotope undergoes radioactive decay by emitting radiation that has a –1 charge. What other characteristic does the radiation
2 answers:
<u>Answer:</u> The radiation emitted will have negligible mass number.
<u>Explanation:</u>
Radioactive decay is defined as the process in which an unstable nuclei breaks down into stable nuclei via various methods.
An isotope undergoes a radioactive decay to attain stability.
There are three types of decay process, but the process in which the emitted radiation carries a charge of -1 is beta decay.
Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron. In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units. The released beta particle is also known as electron.
Hence, the radiation emitted will have negligible mass number.
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Answer:
Approximately .
Explanation:
This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.
This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:
,
where
is the final velocity of the moving object,
is the initial velocity of the moving object,
is the (linear) acceleration of the moving object, and
is the (linear) displacement of the object while its velocity changed from
The angular analogue of that equation will be:
, where
and
are the initial and final angular velocity of the rotating object,
is the angular acceleration of the moving object, and
is the angular displacement of the object while its angular velocity changed from
For this object:
, whereas
.
The question is asking for an angular acceleration with the unit . However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:
.
Rearrange the equation and solve for
:
.