An isotope undergoes radioactive decay by emitting radiation that has a –1 charge. What other characteristic does the radiation
2 answers:
<u>Answer:</u> The radiation emitted will have negligible mass number.
<u>Explanation:</u>
Radioactive decay is defined as the process in which an unstable nuclei breaks down into stable nuclei via various methods.
An isotope undergoes a radioactive decay to attain stability.
There are three types of decay process, but the process in which the emitted radiation carries a charge of -1 is beta decay.
Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron. In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units. The released beta particle is also known as electron.
Hence, the radiation emitted will have negligible mass number.
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Answer:
= 285 Joules
Explanation:
a) answer can be found out in attachment
(b) The temperature for the isothermal compression is the same as the temp at the end of the isobaric expansion. Since pressure is held constant but volume doubles, we use the ideal gas law:
p V = nR T to see that the temperature also doubles.
.So... temp for isothermal compression = 355×2 = 710 K
.(c) The max pressure occurs at the top point. At this point, the volume is back to the original value but the temperature is twice the original value. So the pressure at this point is twice the original, or
max pressure = 2×240000 Pa = 480000 Pa = 4.80 x 10^5 Pa
(d) total work done by the piston = workdone during isothermal compression - work done during expansion =
= nRT ln(V initial / V final)-p (V initial - V final)
= nRT ln(2) - nR(T final - T initial)
= 0.250× 8.314 ×710×ln(2)-0.250×8.314× (710 - 355)
= 285 Joules
Answer:
D. Q/2
Explanation:
See attached file
