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4 years ago

In a clock, the average speed is maximum for the tip of<br />a) Seconds hand b) Hours hand c) Minutes hand

Physics

2 answers:

vodka [1.7K]4 years ago

8 0

Answer:

second hand is correct answer

Simora [160]4 years ago

3 0

A, hope this helped! I didn’t really get it but I think it’s correct?

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Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/a in 20 s. What is te net force acting on the body?

Strike441 [17]

The guy below is wrong!

F=ma
Where force = mass x acceleration

We dont have acceleration, a= change in velocity divided by the time taken.
a = v (final velocity) - u (initial) / t
a us 8-0 (at rest means u was 0) / 20 = 0.4

Using F=ma

F= mass x acceleration
F= 4 x 0.4
F=1.6 N

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3 years ago

What two units of air pressure are commonly used in weather reports?

konstantin123 [22]

The two units are Inches of Mercury and Millibars

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3 years ago

The radiation detector that uses detection of flashes of light is a _____

Maslowich

The radiation detector that uses detection of flashes of light is a <u>scintillation counter.</u>

<h3>What is a scintillation counter?</h3>

A scintillation counter detects and measures ionizing radiation by using the excitation action of incoming radiation on a scintillating substance and detecting the light pulses that arise.

One of the most critical considerations for anyone who operate with or near radiation is being aware of the amounts of radiation present.

This is generally performed through the use of several types of radiation detectors.

The radiation detector that uses detection of flashes of light is a scintillation counter.

Hence,scintillation counter is the correct answer.

To learn more about the scintillation counter, refer:

brainly.com/question/12763694

#SPJ4

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2 years ago

A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,

alexgriva [62]

The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
$S= \frac{1}{2} a t^2$
where a is the acceleration. Using the data of the problem, we can find a:
$a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2$
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J$

and so the power output is
$P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W$

b) power output at t=4.0s
The velocity at t=4.0 s is
$v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J$

and so the power output is
$P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W$

c) Power output at t=6.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J$

and so the power output is
$P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W$

8 0

3 years ago

The apparent reversal of motion of planets against the backdrop of fixed stars is called

Free_Kalibri [48]

The planets move eastward against the background of fixed stars with the exception of Venus, Uranus and Pluto moving westward as seen in Earth's sky . This apparent retreating movement is called Retrograde motion. It is illusion created by Earth's movement going by outer planets in their respective orbits.

7 0

3 years ago

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In a clock, the average speed is maximum for the tip of<br />a) Seconds hand b) Hours hand c) Minutes hand​

In a clock, the average speed is maximum for the tip of<br />a) Seconds hand b) Hours hand c) Minutes hand