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Burka [1]
3 years ago
11

A particular brand of gasoline has a density of .737g/mL at 25 C. How many grams of this gasoline would fill a 14.1 gal tank (1

US gal = 3.78L)?
Chemistry
1 answer:
Ivan3 years ago
6 0

Answer: 5.06g/mL

Explanation: 14.1÷.737=19.131614654

19.131614654/3.78= 5.0612

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What types of matter consist of particles that are highly organized?
Luda [366]

Answer: Solids

Explanation:

Solids have a definite volume and structure. These are comprised of atoms, ions, and molecules closely packed together giving a confined structure to the solids. The particles are bound with strong force of attraction. The particles in the solid are arranged in an repeated, orderly, and three dimensional pattern. Depending upon the substance of the solid the particles within the solid can be ions, atoms, and can be molecules.

4 0
2 years ago
PLS HELP ME WITH THIS ILL GIVE BRAINLIEST
anyanavicka [17]

Answer:

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6 0
2 years ago
What would be the greatest difference in using an open ceramic coffee mug rather than an insulated mug with a lid as a calorimet
STALIN [3.7K]

Answer:

Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

6 0
2 years ago
Read 2 more answers
The equilibrium constant has been estimated to be 0.12 at 25 °C. If you had originally placed 0.069 mol of cyclohexane in a 2.8
scZoUnD [109]

Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively

Explanation:

Moles of cyclohexane = 0.069 mole

Volume of solution = 2.8 L

Initial concentration of cyclohexane =\frac{moles}{Volume}=\frac{0.069}{2.8}=0.025M

The given balanced equilibrium reaction is,

                            cyclohexane  ⇔  methylcyclopentane

Initial conc.                 0.025 M           0

At eqm. conc.       (0.025-x)M       (x) M

The expression for equilibrium constant for this reaction will be,

K= methylcyclopentane / cyclohexane

Now put all the given values in this expression, we get :

0.12=\frac{(x)}{(0.025-x)}

By solving the term 'x', we get :

x =  0.0027

Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M

Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M

4 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0°c is 4.48. what is the value of ka for hbro?
elena-14-01-66 [18.8K]

The solution would be like this for this specific problem:

Given:

 

pH of a 0.55 M hypobromous acid (HBrO) at 25.0 °C =  4.48

 

[H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-] <span>

Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>

 

To add, Hypobromous Acid does not require acid adjustment, which is necessary for chlorine-based product and is stable and effective in pH ranges of 5-9.<span>

</span>Hypobromous Acid combines with organic compounds to form a bromamine. Chlorine also combines with the same organic compounds to form a chloramine. <span>It is also one of the least expensive intervention antimicrobial compounds available.</span>

8 0
3 years ago
Read 2 more answers
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