The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s
Why?
To solve the problem, we must consider the vertical height reached by the student as max height.
We can use the following equations to solve the problem:
<u>Initial speed calculations:</u>
At max height, the speed tends to zero.
So, calculating, we have:
<u>
</u>
<u>Hang time calculations:</u>
We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:
Then, for the total hang time, we have:
Have a nice day!
Answer:
8.24 m/s
Explanation:
Given:
t = 2.10 s
v₀ᵧ = 0 m/s
vₓ = 22.2 cos(-68.2) m/s
aₓ = 0 m/s²
Find: v₀
In the x direction:
v = at + v₀
22.2 cos(-68.2) = (0) (2.10) + v₀ₓ
v₀ₓ = 8.24
v₀² = v₀ₓ² + v₀ᵧ²
v₀² = (8.24)² + (0)²
v₀ = 8.24 m/s
Answer:
The correct answer is - 200000 J
Explanation:
We use the formula of kinetic energy:
The formula to calculate kinetic energy is,
Here,
Ec =1/2 x m x v^2
The mass of the roller coaster is, m = 1000 k
g
The speed of the roller coaster is, v = 20.0 m/s
Therefore,
Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule
200,000J
Explanation:
a. " for every action there is an equal and opposite reaction".
b. The electric fan does not stop moving just after the switch turns off because of rational inertia force.
c. The force applied to first vehicle is 120N.
d. In my view it doesn't support the law of conservation of momentum. Momentum of 1 and 2 object before the collision is equal to the total momentum of two object after collision.
Answer:
120N
Explanation:
Newton's second law formula: F= ma
given that m = 10 kg, a = 12 m/s^2
F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N
