The net force on the object is zero, so it has no acceleration. It moves in a straight line and at a constant speed (which may be zero).
Given :
The acceleration due to gravity on or near the surface of Earth is 32 ft/s/s
To Find :
From what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft/s.
Solution :
Initial velocity of stone, u = 0 ft/s.
Now, by equation of motion :
Therefore, height from which stone is thrown is 289 ft.
If you meant solve, the answer would be v= A times t
You see, to get rid of an variable on one side, you must do the opposite of what is being done to it, in this case, multiply because division. After this, we must do what we did to one side to the other side. This creates the equation above!
The gravitational field strength creates forces on mass by pulling it towards the centre the equation is weight=mass*gravitational field strength
A. Rain falling from the sky.
