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sergey [27]
3 years ago
7

What is formula mass?

Chemistry
1 answer:
babymother [125]3 years ago
5 0
Fórmula masssssss !!!!
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CHEM HELP PLEASE
natka813 [3]

Answer:

90.2%

Explanation:

% yield = actual yield/ theoretical yield * 100%

% yield = (312/346)*100% = 90.2%

3 0
3 years ago
PLEASE HELP MEEE!!! A group of students performed an experiment in which they dropped a cube of metal into a graduated cylinder
lianna [129]

Answer:

10 cal

Explanation:

No Explanation

7 0
3 years ago
Atoms of one element are converted to atoms of another element through
lubasha [3.4K]
Atoms of one element are converted to atoms of another element through transmutation or nuclear transmutation.
6 0
3 years ago
How many phase rule variables must be specified to fix the thermodynamic state of each of the following systems? Show how you de
Murrr4er [49]

Answer: (i) F = 2

(ii) F = 3

(iii) F = 2

Explanation:

We would be applying the famous Gibbs Phase Rule to explaining this problem;

By applying the formula;

F+P = C +2

Where P = this represent the phase

F = this is called the degree of freedom

C = this represent the component in the system

Ok let us begin;

(i). from this we can see that there are 2 components i.e. (water + ethanol) and the phase in question is a vapor phase + liquid phase.

So from the formula;

F = C-P+2

F = 2 – 2 + 2 = 2

Therefore, F = 2.

(ii). Also, from the statement, we can figure there are 3 components, while the phases are two like the previous one above, i.e. liquid + vapor

F = 3 – 2 + 2 = 5 – 2 = 3

F = 3

(iii). From this statement, we can figure there are 3 components, and the phases are 3 i.e. (2 liquid phases + 1 vapor phase)

From the formula;

F = 3 – 3 + 2 = 0 + 2

F = 2

6 0
4 years ago
Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine
Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound  

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0
3 years ago
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