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2 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Chemistry

1 answer:

Phoenix [80]2 years ago

6 0

Answer: Option (B) is the correct answer.

Explanation:

It is known that for writing a chemical reaction equation, reactants are written on left hand side whereas products are written on right hand side.

And in between reactants and products a forward arrow is placed pointing towards the products.

Therefore, the reaction for carbon burns in the presence of oxygen to give carbon dioxide will be written as follows.

$Carbon + Oxygen \rightarrow Carbon dioxide$

Here, carbon and oxygen atoms are the reactants whereas carbon dioxide is the product.

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A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

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Which product formed when MgO and H2O react together?

seropon [69]

When MgO and H2O react they form Magnesium Hydroxide Mg(OH)2

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3 years ago

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In the alpha decay of Francium-221, what daughter element is produced?

aleksley [76]

<span>Astatine-217 is the daughter element produced by the alpha decay of Francium-221.</span>

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2 years ago

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What is an expression of Boyle's law (k = constant)?

Leni [432]

Answer:

C.) PV = k

Explanation:

Boyle's Law is a variation of the Ideal Gas Law when all variables, except for pressure and volume, are held constant.

Pressure is represented by "P" and volume is represented by "V". In the Ideal Gas Law, pressure and volume are inversely proportional (if one goes up, the other goes down). That being said, the equation which best represents Boyle's Law is PV = k.

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