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andrew-mc [135]
4 years ago
9

A 9-m length of 6-mm-diameter steel wire is to be used in a hanger. The wire stretches 18mm when a tensile force P is applied. I

f E = 200 GPa, determine the magnitude of the force P, and the normal stress in the wire.
Engineering
1 answer:
worty [1.4K]4 years ago
4 0

Force P is 11304 N and normal stress is 400 N/mm²

<u>Explanation:</u>

Given-

Length, l = 9 m = 9000 mm

Diameter, d = 6 mm

Radius, r = 3 mm

Stretched length, Δl= 18 mm

Modulus of elasticity, E = 200 GPa = 200 X 10³MPa

Force, P = ?

According to Hooke's law,

Stress is directly proportional to strain.

So,

σ ∝ ε

σ = E ε

Where, E is the modulus of elasticity

We know,

ε = Δl / l

So,

σ = E X Δl/l

σ =

200 X 10^3 * \frac{18}{9000} \\\\ = 400N/mm^2

We know,

σ = P/A

And A = π (r)²

σ = P / π (r)²

400 N/mm^2 = \frac{P}{3.14 X (3)^2} \\\\400 = \frac{P}{28.26} \\\\P = 11304N

Therefore, Force P is 11304 N and normal stress is 400 N/mm²

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Biologists use a sequence of letters A, C, T, and G to model a genome. A gene isa substring of a genome that starts after a trip
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Answer:

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import java.util.Scanner; // to get input from user

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Explanation:

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