Answer:
The capacity of the sludge pump is 0.217 m3/min
Explanation:
Solution is attached below
Answer:
(d) 2 pF
Explanation: the charge on capacitor is given by the expression
Q=CV
where Q=charge
C=capacitance
V=voltage across the plate of the capacitor
here we have given Q=500 pF, V=250 volt
using this formula C=
=500××
=2×
=2 pF
Answer:
3.59
4.32
Explanation:
We find the time factors and engine factor to solve for this.
Engine factor = (100%*15/60) + (60%*30/60) + (20%*15/60)
= 1x0.25 + 0.6x0.5 + 0.2x0.25
= 0.25 + 0.30 + 0.05
= 0.6
A. We find time factor
= 50/60 = 0.83 minutes
We then get consumption
= Time factor x engine x hp x .04
= 0.83 x 0.6 x 180 x 0.04
= 3.585
3.59 gallons in 1 hr
B. Time factor = 60/60 = 1
Consumption =
1x0.6x180x0.04
= 4.32 gallons in 1 hour