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3 years ago

11

Is anyone bored? could they do 37 pages of notes for my AP world history

1 answer:

sashaice [31]3 years ago

6 0

You finna have to pay me lol what it look like though and i’ll see if it’s worth it make some

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What is the name of the force that slows it down?.

Rus_ich [418]

Gravity pulls to the centre of the earth. A ship floats in water because the water pushing it up (upthrust) is equal to the force<span> of gravity (weight) pulling it </span>down<span>. Friction also occurs when objects move through air. This is </span>called<span>air resistance.</span>

6 0

3 years ago

Assuming the ball's initial velocity was 51 ∘ above the horizontal and ignoring air resistance, what did the initial speed of th

Umnica [9.8K]

horizontal distance of home run is 400 ft = 122 m

height of the home run is 3 ft = 0.9 m

now the angle of the hit is 51 degree

now we have equation of trajectory of the motion

$x = vcos\theta * t$

$y = v sin\theta * t - \frac{1}{2} gt^2$

solving above two equations we have

$y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}$

now here we will plug in all data

$0.9 = 122 tan51 - \frac{9.8 * 122^2}{2*v^2 * cos^251}$

$0.9 = 150.65 - \frac{184150.2}{v^2}$

$\frac{184150.2}{v^2} = 149.75$

$v = 35.1 m/s$

<em>so the ball was hit with speed 35.1 m/s from the ground</em>

8 0

3 years ago

A pressure of 70N/m2 equals

laiz [17]

Answer:

Newton/square meters=70 AND Pascal=70

Explanation:

Formula:multiply the pressure value by 1.

6 0

3 years ago

Leto [7]

True
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True
My answers

4 0

4 years ago

What force, in newtons, must you exert on the balloon with your hands to create a gauge pressure of 62.5 cm H2O, if you squeeze

yulyashka [42]

Answer:54.70 N

Explanation:

Given

Gauge Pressure of $62.5 cm of H_2O$

i.e. $h=62.5 cm =0.625 m$

Effective area $A=51 cm^2$

initial Pressure $= 1 atm=101.325 kPa$

Gauge Pressure $P=\rho gh$

$\rho =density\ of\ water =1000 kg/m^3$

$P_{gauge}=1000\times 9.8\times 0.625=5.937 kPa$

Force creates a pressure of $P_1$ which will be equal to Gauge Pressure

$P_1=\frac{F}{A}$

$P_1=P_{gauge}$

$\frac{F}{A}=5.937 kPa$

$F=5.937\times 51\times 10^{-4}\times 10^3$

$F=30.27 N$

6 0

4 years ago