Answer:
(a) 9444.4 V/m
(b) 3.72×10⁻¹² F
(c) 6.324×10⁻¹¹ C
Explanation:
(a)
The formula of electric field is given as
E = V/r ......................... Equation 1
Where E = Electric Field, V = Electric potential, r = distance between the plates of the capacitor.
Given: V = 17.0 V, r = 1.8 mm = 0.0018 m.
Substitute into equation 1
E = 17.0/0.0018
E = 9444.4 V/m.
(b)
The formula of the capacitance of a capacitor is given as,
C = ε₀A/d .......................... Equation 2
Where C = Capacitance of the capacitor, ε₀ = permitivity of free space, d = distance between the plates, A = Area of each plate.
Given: A = 7.6 cm² = 0.00076 m³, d = 1.8 mm = 0.0018 m.
Constant: 8.854×10⁻¹² F/m.
Substitute into equation 2
C = 8.854×10⁻¹²(0.00076)/0.0018
C = 3.72×10⁻¹² F.
(c)
The charge stored in a capacitor is given as,
q = CV................... Equation 3
Where q = charge, V = Voltage applied across the plate of the capacitor.
Given: V = 17.0 V, C = 3.72×10⁻¹² F
Substitute into equation 3
q = 17(3.72×10⁻¹²)
q = 63.24×10⁻¹²
q = 6.324×10⁻¹¹ C
