Answer:
5040 watts
Explanation:
Power (P) = electric current (I) × Time (T)
P = 400 × 12.6
P = 5040 watts
Answer:
Q = 8.845 DEGREE
Explanation:
given data:
combine Mass for 6 cylinder (M) =15 Kg/hr
mass of each cylinder (m) = 15/6 = 2.5 Kg/hr = 0.000694 Kg/ sec
Engine speed (N)= 1500rpm
Diameter of one nozzle hole ( d) = 200 micrometer = 0.0002 m
Discharge Coefficient (Cd) = 0.75
Pressure difference = 100 MPa
Density of fuel = 800 kg/m^3
velocity of fuel is
injected fuel volume (V) =Area of given Orifices × Fuel velocity × time of single injection × no of injection/sec
we know that p = m/ V
So
putting these value in volume equation and solve for Discharge
Q = 8.845 DEGREE
Answer:
Explanation:
Elimination 1
Substitution 2
Engineering Controls 3
Administrative Controls 4
PPE 5
Answer:
A)
B)
Explanation:
Given data:
P-1 = 100 lbf/in^2
degree f
effeciency = 80%
from steady flow enerfy equation
where h1 and h2 are inlet and exit enthalpy
for P1 = 100 lbf/in^2 and T1 = 500 degree F
for P1 = 40 lbf/in^2
exit enthalapy h_2
from above equation
[1 Btu/lbm = 25037 ft^2/s^2]
b) amount of entropy
at
Answer:
Explanation:
The detailed analysis, with free body diagram and step by step calculations with appropriate substitution is as shown in the attached files.