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Kamila [148]
4 years ago
14

A college student wakes up hungry. He turns on the coffee maker (average wattage 1200 W), puts some oatmeal in the microwave ove

n (1450 W) to cook, puts a couple of slices of bread in the toaster (1146 W), and starts making scrambled eggs in the electric frying pan (1196 W). All of these appliances in his dorm room are supplied by a 120 V (rms) branch circuit protected by a 50 A (rms) circuit breaker.
Determine the total rms current in the current breaker.
Engineering
1 answer:
AysviL [449]4 years ago
8 0

Answer:

41.6 A

Explanation:

Total power drawn = 1200 W + 1450 W + 1146 W + 1196 W = 4992 W

Power P = IV

I = P/V

Where I is the rms current,

V is the voltage = 120 V

I = 4992/120 = 41.6 A

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Design a plate and frame heat exchanger for the following problem:
qwelly [4]

Answer:

See explaination and attachment.

Explanation:

Iteration method is a repetitive method applied until the desired result is achieved.

Let the given equation be f(x) = 0 and the value of x to be determined. By using the Iteration method you can find the roots of the equation. To find the root of the equation first we have to write equation like below

x = pi(x)

Let x=x0 be an initial approximation of the required root α then the first approximation x1 is given by x1 = pi(x0).

Similarly for second, thrid and so on. approximation

x2 = pi(x1)

x3 = pi(x2)

x4 = pi(x3)

xn = pi(xn-1).

please go to attachment for the step by step solution.

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3 years ago
I need ideas of usernames for a 2021 Jeep Wrangler Rubicon!!
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Answer:

2021 super star wagon master

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3 years ago
technician a says that dirt bypassing the filter on many common rail injectors can cause an injector to stick open and continuou
NNADVOKAT [17]

Technician a is correct because he says that Many common rail injectors filters can be bypassed by dirt, which can lead to an injector sticking open and continuously fueling a cylinder.

Coalescence is used to separate the water and fuel. To the fuel injector cleaning kit, fasten your air compressor. Diesel engines run at compression ratios that are greater than those of gasoline engines. greater ratio compared to gasoline engines. increased thermal expansion as a result. more fuel energy that is transformed into usable power. The great benefit of using a dry cylinder sleeve is that by quickly installing new sleeves, the cylinder block can be quickly restored to its original specifications. Vacuum drying can be used to get rid of small amounts of water. A nozzle is used to spray the fuel into the vacuum chamber of engines. Air and unsolved free water are taken out of the oil. The fuel is evenly dispersed, which facilitates efficient drying.

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3 0
1 year ago
An engineering drawing shows the: (A) dimensions, tolerances, cost, and sales or use volume of a component.(B) dimensions, toler
Leto [7]

Answer:

(B) dimensions, tolerances, materials, and finishes of a component.

Explanation:

An engineering drawing :

  An  engineering drawing is a technical drawing which draws the actual component .

An engineering drawing shows

1. Materials

2.Dimensions

3.Tolerance

4.Finishes of a component

Engineering drawing does not shows any information about the cost of component.

So the option B is correct.

3 0
3 years ago
Air in a large tank at 300C and 400kPa, flows through a converging diverging nozzle with throat diameter 2cm. It exits smoothly
-Dominant- [34]

Answer:

The answer is "3.74 \ cm\ \ and \ \ 0.186 \frac{kg}{s}"

Explanation:

Given data:  

Initial temperature of tank T_1 = 300^{\circ}\ C= 573 K

Initial pressure of tank P_1= 400 \ kPa

Diameter of throat d* = 2 \ cm

Mach number at exit M = 2.8

In point a:

calculating the throat area:

A*=\frac{\pi}{4} \times d^2

      =\frac{\pi}{4} \times 2^2\\\\=\frac{\pi}{4} \times 4\\\\=3.14 \ cm^2

Since, the Mach number at throat is approximately half the Mach number at exit.  

Calculate the Mach number at throat.  

M*=\frac{M}{2}\\\\=\frac{2.8}{2}\\\\=1.4

Calculate the exit area using isentropic flow equation.

\frac{A}{A*}= (\frac{\gamma -1}{2})^{\frac{\gamma +1}{2(\gamma -1)}}  (\frac{1+\frac{\gamma -1}{2} M*^2}{M*})^{\frac{\gamma +1}{2(\gamma -1)}}

Here: \gamma is the specific heat ratio. Substitute the values in above equation.

\frac{A}{3.14}= (\frac{1.4-1}{2})^{-\frac{1.4+1}{2(1.4 -1)}}  (\frac{1+\frac{1.4-1}{2} (1.4)^2}{1.4})^{\frac{1.4+1}{2(1.4-1)}} \\\\A=\frac{\pi}{4}d^2 \\\\10.99=\frac{\pi}{4}d^2 \\\\d = 3.74 \ cm

exit diameter is 3.74 cm

In point b:

Calculate the temperature at throat.

\frac{T*}{T}=(1+\frac{\Gamma-1}{2} M*^2)^{-1}\\\\\frac{T*}{573}=(1+\frac{1.4-1}{2} (1.4)^2)^{-1}\\\\T*=411.41 \ K

Calculate the velocity at exit.  

V*=M*\sqrt{ \gamma R T*}

Here: R is the gas constant.  

V*=1.4 \times \sqrt{1.4 \times 287 \times 411.41}\\\\=569.21 \ \frac{m}{s}

Calculate the density of air at inlet

\rho_1 =\frac{P_1}{RT_1}\\\\=\frac{400}{ 0.287 \times 573}\\\\=2.43\  \frac{kg}{m^3}

Calculate the density of air at throat using isentropic flow equation.  

\frac{\rho}{\rho_1}=(1+\frac{\Gamma -1}{2} M*^2)^{-\frac{1}{\Gamma -1}} \\\\\frac{\rho *}{2.43}=(1+\frac{1.4-1}{2} (1.4)*^2)^{-\frac{1}{1.4-1}} \\\\\rho*= 1.045 \ \frac{kg}{m^3}

Calculate the mass flow rate.  

m= \rho* \times A* \times V*\\\\= 1.045 \times 3.14 times 10^{-4} \times 569.21\\\\= 0.186 \frac{kg}{s}

5 0
3 years ago
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