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denis23 [38]
3 years ago
14

Placing a sample of iron (II) oxide into a graduated cylinder makes the water volume increase 12.0 mL. The weight of the sample

is 76.6 g. What is its density?​
Chemistry
2 answers:
yarga [219]3 years ago
4 0

Answer:

6.38

Explanation:

D=M/V

D= 76.6/12.0

D=6.38

Alenkinab [10]3 years ago
3 0

Answer:

Density, d=6.38\ g/cm^3

Explanation:

It is given that, placing a sample of iron (II) oxide into a graduated cylinder makes the water volume increase 12.0 mL.

It means that the volume of the sample is 12 mL

The weight of the sample is 76.6 g

We need to find the density of the sample.

12 mL = 12 cm³

The formula of density is given by :

d=\dfrac{m}{V}\\\\d=\dfrac{76.6\ g}{12\ cm^3}\\\\d=6.38\ g/cm^3

So, the density of the sample is 6.38\ g/cm^3.

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Answer:

See BELOW!

Explanation:

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6 0
3 years ago
In a coffee cup calorimeter, 1.60 g of NH4NO3 is mixed with 75.0 g of water at an initial temperature of 25.00 degrees C. After
igomit [66]

Answer:

+26.6kJ/mol

Explanation:

The enthalpy of dissolution of NH₄NO₃ is:

NH₄NO₃(aq) + ΔH  → NH₄⁺ + NO₃⁻

Where ΔH is the heat of reaction that is absorbed per mole of NH₄NO₃,

The moles that reacts in 1.60g are (Molar mass NH₄NO₃:80g/mol):

1.60g * * (1mol / 80g) = 0.02 moles reacts

To find the heat released in the coffee cup calorimeter, we must use the equation:

Q = m×ΔT×C

Where Q is heat released,

m is mass of the solution

ΔT is change in temperature (Final temperature - Initial temperature)

C is specific heat of the solution (4.18J/g°C)

Mass of the solution is:

1.60g + 75g = 76.60g

Change in temperature is:

25.00°C - 23.34°C = 1.66°C

Replacing:

Q = m×ΔT×C

Q = 76.60g×1.66°C×4.18J/g°C

Q = 531.5J

This is the heat released per 0.02mol. The heat released per mole (Enthalpy change for the dissolution of NH₄NO₃) is:

531.5J / 0.02mol = 26576J/ mol =

+26.6kJ/mol

<em>+ because the heat is absorbed, the reaction is endothermic-</em>

7 0
3 years ago
Please help me, thank you
Bezzdna [24]

Answer:

it's C

Explanation:

Yes

5 0
3 years ago
Read 2 more answers
When the products of a reaction are hotter than the reactants:
kobusy [5.1K]
A.) The reaction is Exothermic
5 0
3 years ago
What is the pH of .0003 M of NaOH
s344n2d4d5 [400]

We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

<u>pOH of the solution:</u>

pOH = -log[OH⁻] = -log(3 * 10⁻⁴)

pOH = -0.477 + 4

pOH = 3.523

<u>pH of the solution:</u>

We know that the sum of pH and pOH of a solution is 14

pH + pOH = 14

pH + 3.523 = 14                              [subtracting 3.523 from both sides]

pH = 10.477                        

8 0
3 years ago
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