Answer:
a) C= 1/120
b) P(X>=5) = 0.333
Explanation:
The attached file contains the explanation for the answers
Answer:
A working with machinery be a common type of caught-in and caught-between hazard is described below in complete detail.
Explanation:
“Caught in-between” accidents kill mechanics in a variety of techniques. These incorporate cave-ins and other hazards of tunneling activity; body parts extracted into unconscious machinery; reaching within the swing range of cranes and other installation material; caught between machine & fixed objects.
Answer:
The shear strain is 0.05797 rad.
Explanation:
Shear strain is the ratio of change in dimension along the shearing load direction to the height of the plate under application of shear load. Width of the plate remains same. Length of the plate slides under shear load.
Step1
Given:
Height of the pad is 1.38 in.
Deformation at the top of the pad is 0.08 in.
Calculation:
Step2
Shear strain is calculated as follows:



For small angle of
,
can take as
.

Thus, the shear strain is 0.05797 rad.
Answer:
1. cout << "Num: " << songNum << endl;
2. cout << songNum << endl;
3. cout << songNum <<" songs" << endl;
Explanation:
//Full Code
#include <iostream>
using namespace std;
int main ()
{
int songNum;
songNum = 5;
cout << "Num: " << songNum << endl;
cout << songNum << endl;
cout << songNum <<" songs" << endl;
return 0;
}
1. The error in the first cout statement is that variable songnum is not declared.
C++ is a case sensitive programme language; it treats upper case and lower case characters differently.
Variable songNum was declared; not songnum.
2. Cout us used to print a Variable that has already been declared.
The error arises in int songNum in the second cout statement.
3. When printing more than one variables or values, they must be separated with <<
The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is <u>5kJ</u>.
Define work. Explain the rate of doing work.
Work is <u>the energy that is moved to or from an item by applying force along a displacement</u> in physics. For a constant force acting in the same direction as the motion, work is <u>easiest expressed as the product of </u><u>force </u><u>magnitude and distance traveled</u>.
Since the <u>force </u><u>transfers one unit of energy for every unit of </u><u>work </u><u>it performs</u>, the rate at which work is done and energy is used are equal.
Solution Explained:
Given,
Weight = 1000N and distance = 5m
A/Q, the work here is done in lifting then
Work = (weight) × (distance moved)
= 1000 X 5
= 5000Nm or 5000J = 5kJ
Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
To learn more about work, use the link given
brainly.com/question/25573309
#SPJ9
<u />