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Sophie [7]
3 years ago
13

119 mL of 4.0 M H2SO4 with 229 mL of H2O

Chemistry
1 answer:
motikmotik3 years ago
4 0

Answer:

Uhhhu

Explanation:

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Can someone pls help me with this pls
Slav-nsk [51]

Answer:

I would say element

Explanation:

because it is made of two different types of atoms chemically bonded together!

I'm sorry if wrong!

8 0
3 years ago
Please help, I will give brainylest
Anna [14]

Answer:

Explanation:

Divide both of the like fractions, then multiply the answers even if their iregular.

5 0
3 years ago
Ventilator should be kept in our room give reasons of science ​
Firlakuza [10]

Answer:

Ventilators are provided in the rooms at the top of the roofs because if the air inside the room gets hot, the hot air rises up and flows through these ventilators and thus cool air remains at bottom. Thus ventilators maintain conventional currents to keep the air fresh in the room.

Explanation:

7 0
3 years ago
Read 2 more answers
0=4<br> Balance this equation<br> H₂sicl2+ H₂O → H8Si4O4 + HCl
zaharov [31]

Balanced Equation is

4H2SiCl2+4H2O → H8Si4O4 + 8HCl

8 0
3 years ago
5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H
cricket20 [7]
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0
3 years ago
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