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k0ka [10]
3 years ago
11

To what volume must 557 mL of 11 M

Chemistry
1 answer:
notka56 [123]3 years ago
6 0

Answer:

The answer to your question is the number 4. 1.53175 L

Explanation:

Data

Volume 1 = V1 = 557 ml

Concentration 1 = C1 = 11 M

Volume 2 = V2 = ?

Concentration 2 = C2 = 4 M

Formula

            Volume 1 x Concentration 1 = Volume 2 x Concentration 2

or                                           V1 x C1 = V2 x C2

Solve for V2                                 V2 = V1 x C1 / C2

-Substitution

                                                     V2 = (557)(11) / 4

-Simplification

                                                     V2 = 6127 / 4

-Result

                                                     V2 = 1531.75 ml or 1.53175 L

Conclusion

557 ml of 11 M must be diluted to 1.53175 L

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A chemist dissolves of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (The t
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Answer:

12.99

Explanation:

<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>

Step 1: Given data

  • Mass of KOH: 716. mg (0.716 g)
  • Volume of the solution: 130. mL (0.130 L)

Step 2: Calculate the moles corresponding to 0.716 g of KOH

The molar mass of KOH is 56.11 g/mol.

0.716 g × 1 mol/56.11 g = 0.0128 mol

Step 3: Calculate the molar concentration of KOH

[KOH] = 0.0128 mol/0.130 L = 0.0985 M

Step 4: Write the ionization reaction of KOH

KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)

The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M

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We will use the following expression.

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Answer:

2.067 L ≅ 2.07 L.

Explanation:

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It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

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<u><em>using cross multiplication:</em></u>

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  • To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:

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0.1384 mol of O₂ produce → ??? mol of SO₂.

∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.

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