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k0ka [10]
4 years ago
11

To what volume must 557 mL of 11 M

Chemistry
1 answer:
notka56 [123]4 years ago
6 0

Answer:

The answer to your question is the number 4. 1.53175 L

Explanation:

Data

Volume 1 = V1 = 557 ml

Concentration 1 = C1 = 11 M

Volume 2 = V2 = ?

Concentration 2 = C2 = 4 M

Formula

            Volume 1 x Concentration 1 = Volume 2 x Concentration 2

or                                           V1 x C1 = V2 x C2

Solve for V2                                 V2 = V1 x C1 / C2

-Substitution

                                                     V2 = (557)(11) / 4

-Simplification

                                                     V2 = 6127 / 4

-Result

                                                     V2 = 1531.75 ml or 1.53175 L

Conclusion

557 ml of 11 M must be diluted to 1.53175 L

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The equilibrium concentrations of the reactants and products are [ HA ] = 0.260 M [HA]=0.260 M , [ H + ] = 2.00 × 10 − 4 M [H+]=
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Answer:

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Explanation:

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So at equilibrium, Ka is calculated as below

Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260

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While estimating the Caloric content of the chemical constituents present in the food item, the carbohydrate amount is discounte
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How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
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= 46.06 grams

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Hydrogen gas is filled in a 224 ml glass container at 0 degree celcius and 1 atmospheric pressure. What are the number of molecu
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Answer:

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8 0
4 years ago
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