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k0ka [10]
4 years ago
11

To what volume must 557 mL of 11 M

Chemistry
1 answer:
notka56 [123]4 years ago
6 0

Answer:

The answer to your question is the number 4. 1.53175 L

Explanation:

Data

Volume 1 = V1 = 557 ml

Concentration 1 = C1 = 11 M

Volume 2 = V2 = ?

Concentration 2 = C2 = 4 M

Formula

            Volume 1 x Concentration 1 = Volume 2 x Concentration 2

or                                           V1 x C1 = V2 x C2

Solve for V2                                 V2 = V1 x C1 / C2

-Substitution

                                                     V2 = (557)(11) / 4

-Simplification

                                                     V2 = 6127 / 4

-Result

                                                     V2 = 1531.75 ml or 1.53175 L

Conclusion

557 ml of 11 M must be diluted to 1.53175 L

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FeCl3 + NaOH → Fe(OH)3 + NaCl​
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Answer:

FeCl₃  +  <u>3</u>NaOH  →  Fe(OH)₃  +  <u>3</u>NaCl​

Explanation:

You are given a skeleton equation, or unbalanced equation.

FeCl₃  +  NaOH  →  Fe(OH)₃  +  NaCl​

<u>Count the number of atoms on each side</u>. If there is 1 atom, the subscript is not written. If the subscript to the right of a bracket, it belongs to each element in the bracket.

Reactants     →       Products

Fe  1                        Fe  1

Cl   3                       Cl   1         Not balanced

Na  1                        Na  1

O   1                         O   3        Not balanced

H   1                         H   3        Not balanced

<u>The number of each element must be the same in the reactants and products.</u> We can see that Cl (chlorine), O (oxygen) and H (hydrogen) have different numbers.

<u>Write in coefficients in front of formulas</u> (separated by + sign). Coefficients multiply each subscript (or "1" if not written) in the formula. <u>Recount the atoms until you have equal reactant and product atom numbers.</u>

I see that I need more chlorine in my products. Multiply the formula that has "Cl" by 3.

FeCl₃  +  NaOH  →  Fe(OH)₃  +  3NaCl​

Reactants     →       Products

Fe  1                        Fe  1

Cl   3                       Cl   3          Cl is balanced now.

Na  1                        Na  3         Not balanced

O   1                         O   3         Not balanced

H   1                         H   3         Not balanced

Fix the "Na" now. Multiply the formula with "Na" on the left by 3.

FeCl₃  +  3NaOH  →  Fe(OH)₃  +  3NaCl​

Reactants     →       Products

Fe  1                        Fe  1

Cl   3                       Cl   3

Na  3                       Na  3

O   3                        O   3

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Balanced formula:

FeCl₃  +  <u>3</u>NaOH  →  Fe(OH)₃  +  <u>3</u>NaCl​

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against at -20 degree centigrade occupied the volume of one 40 ml calculate the temperature at which the volume of cash pickup 6
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<h3>Further explanation</h3>

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