Question

If a sample of a(g) at 3.60 atm is heated to 500 k, what is the pressure of b(g) at equilibrium?

Answer 1

Answer:

Explanation:

Hello,

For the given reaction:

$2A(g)\rightleftharpoons B(g) ; Kp=9.58x10^{-5}$

In such a way, the law of mass action, in terms of the pressures of both A and B at equilibrium result:

$Kp=\frac{p_B}{p_A^2}$

Thus, by introducing the change $x$, due to equilibrium, we obtain:

$Kp=\frac{x}{(p_A_0-2x)^2}$

Hence, solving for $x$ by solver or quadratic equation, we get:

$x=1.24x10^{-3}atm$

Finally, since the pressure of B at equilibrium equals the change, it results:

$p_B^{eq}=1.24x10^{-3}atm$

Best regards.