A circular wooden loop of mass m and radius R rest on a flat horizontal friction less surface. A bullet, also of mass m, and mov
1 answer:
Answer:
w = vR/3
Explanation:
The centre of mass of the loop to bullet system is given by D / 4 from centre of loop, which is equivalent to R / 2 from its centre.
From the principle of conservation of linear momentum , we have
m*v = 2*m* Vcm
Where v = velocity of bullet, Vcm = velocity of wood
Hence, we have
Vcm = v2
Also, from the conservation of angular momentum about the centre of mass.
M*V*(R/2) = Ic*w - equation (I)
where Ic = moment of inertia and w = angular velocity
Ic for a ring is given by
Ic of a bullet is given by
Hence, the moment of inertia of the system is given by the summation of the two moments of inertia Ic(ring) + Ic(bullet) which gives
Ic(system) =
Substituting back into equation (I), we have
Hence, we obtain w =vR/3
w=v3R
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"<span>A small glass bead has been charged to + 25 nC "
Solution
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</span>
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</span>
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Answer:
Amount of linear movement
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, in addition to freight car and sand at time t.
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Answer:
Median
Explanation:
- we commonly use mean as the measure of the center of the data.
- But Median is better measure than mean.
<u>Extra</u><u> </u><u>information</u><u>:</u><u>-</u>
<u>Median</u><u> </u><u>formula</u><u>:</u><u>-</u>